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olga_2 [115]
3 years ago
8

(15/3)*x-2=0 solve for x

Mathematics
1 answer:
ikadub [295]3 years ago
5 0
\dfrac{15}{3}x-2=0. \newline
5x-2=0. \newline
5x=2. \newline
x=\dfrac{2}{5}=0.4.
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The sum of the squares of three consecutive integers is 509. Determine the integers.
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Answer:

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Step-by-step explanation:

Denote the integers as:

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The sum of their squares, so that would be;

(x^(2)) + (( x + 1 )^(2)) + (( x + 2 )^(2)) = 509

write out the squares

x^2 + x^2 + 2x + 1 + x^2 + 4x + 4 = 509

combine like terms

3x^2 + 6x + 5 = 509

inverse operations

3x^2 + 6x + 5 = 509

                -5     -5

3x^2 + 6x = 504

factor

3x^2 + 6x = 504

3 ( x^2 + 2x ) =504

Inverse operations

3 ( x^2 + 2x ) = 504

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x^2 + 2x = 168

Factor again

x ( x + 2 ) = 168

At this point, it should be obvious that x is 12 (because 12 * 14 = 168)

So now substitute back into the consecutive numbers

x = 12

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