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OleMash [197]
3 years ago
9

Find a formula for the given polynomial.

Mathematics
2 answers:
levacccp [35]3 years ago
4 0

In this question, we have to identify the zeros of the polynomial, along with a point, and then we get that the formula for the polynomial is:

p(x) = -0.5(x^3 - x^2 + 6x)

------------------------

Equation of a polynomial, according to it's zeros:

Given a polynomial f(x), this polynomial has roots such that it can be written as: , in which a is the leading coefficient.

------------------------

Identifying the zeros:

Given the graph, the zeros are the points where the graph crosses the x-axis. In this question, they are:

x_1 = -2, x_2 = 0, x_3 = 3

Thus

p(x) = a(x - x_{1})(x - x_{2})(x-x_3)

p(x) = a(x - (-2))(x - 0)(x-3)

p(x) = ax(x+2)(x-3)

p(x) = ax(x^2 - x + 6)

p(x) = a(x^3 - x^2 + 6x)

------------------------

Leading coefficient:

Passes through point (2,-8), that is, when x = 2, y = -8, which is used to find a. So

p(x) = a(x^3 - x^2 + 6x)

-8 = a(2^3 - 2^2 + 6*2)

16a = -8

a = -\frac{8}{16} = -0.5

------------------------

Considering the zeros and the leading coefficient, the formula is:

p(x) = -0.5(x^3 - x^2 + 6x)

A similar problem is found at brainly.com/question/16078990

max2010maxim [7]3 years ago
4 0

The formula that represents the polynomial in the figure is p(x) = x^{3}-x^{2}-6\cdot x.

Based on the Fundamental Theorem of Algebra, we understand that Polynomials with real Coefficient have <em>at least</em> one real Root and <em>at most</em> a number of Roots equal to its Grade. The Grade is the maximum exponent that Polynomial has and root is a point such that p(x) = 0. By Algebra we understand that polynomial can be represented in this manner known as Factorized form:

p(x) = \Pi\limits_{i=0}^{n} (x-r_i) (1)

Where:

n - Grade of the polynomial.

i - Index of the root binomial.

x - Independent variable.

We notice that polynomials has three roots in x = -2, x = 0 and x = 3, having the following construction:

p(x) =(x+2)\cdot x \cdot (x-3)

p(x) = (x^{2}+2\cdot x)\cdot (x-3)

p(x) = x^{3}+2\cdot x^{2}-3\cdot x^{2}-6\cdot x

p(x) = x^{3}-x^{2}-6\cdot x

The formula that represents the polynomial in the figure is p(x) = x^{3}-x^{2}-6\cdot x.

Here is a question related to the determination polynomials: brainly.com/question/10241002

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Answer:

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Two landscapers must mow a rectangular lawn that measures 100 feet by 200 feet. Each wants to mow no more than half of the lawn.
Citrus2011 [14]

The total area of the complete lawn is (100-ft x 200-ft) = 20,000 ft².
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a 2-ft cut, the lengths of the strips he cuts will line up like this:

First lap:
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Second lap:
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       (100 - 6) = 94
       (200 - 6) = 194
       (100 - 8) = 92   

Third lap:
       (200 - 8) = 192
       (100 - 10) = 90
       (200 - 10) = 190
       (100 - 12) = 88 

These are the lengths of each strip.  They're 2-ft wide, so the area
of each one is (2 x the length). 

I expected to be able to see a pattern developing, but my brain cells
are too fatigued and I don't see it.  So I'll just keep going for another
lap, then add up all the areas and see how close he is:

Fourth lap:
       (200 - 12) = 188
       (100 - 14) = 86
       (200 - 14) = 186
       (100 - 16) = 84 

So far, after four laps around the yard, the 16 lengths add up to
2,272-ft, for a total area of 4,544-ft².  If I kept this up, I'd need to do
at least four more laps ... probably more, because they're getting smaller
all the time, so each lap contributes less area than the last one did.

Hey ! Maybe that's the key to the approximate pattern !

Each lap around the yard mows a 2-ft strip along the length ... twice ...
and a 2-ft strip along the width ... twice.  (Approximately.)  So the area
that gets mowed around each lap is (2-ft) x (the perimeter of the rectangle),
(approximately), and then the NEXT lap is a rectangle with 4-ft less length
and 4-ft less width.

So now we have rectangles measuring

         (200 x 100),  (196 x 96),  (192 x 92),  (188 x 88),  (184 x 84) ... etc.

and the areas of their rectangular strips are
           1200-ft², 1168-ft², 1136-ft², 1104-ft², 1072-ft² ... etc.

==> I see that the areas are decreasing by 32-ft² each lap.
       So the next few laps are 
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How much area do we have now:

             After 9 laps,    Area =   9,648-ft²
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And there you are ... Somewhere during the 10th lap, he'll need to
stop and call the company surveyor, to come out, measure up, walk
in front of the mower, and put down a yellow chalk-line exactly where
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5 0
3 years ago
(100+ POINTS)
horsena [70]

Answer:

1) 102.7 meters

2) 11

Step-by-step explanation:

1) -4.9x² + 75x = -4.9x² + 50x + 38

25x = 38

x = 1.52 s

Height = -4.9(1.52)² + 75(1.52) = 102.67904 m = 102.7 m

2) f(x) = x² + 3x - 2

f(2) = 2² + 3(2) - 2 = 8

f(6) = 6² + 3(6) - 2 = 52

Average rate of change:

(52-8)/(6-2) = 11

5 0
3 years ago
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