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Neporo4naja [7]
3 years ago
8

What is the area of the square base of a sandbox, if one side is 6 feet long?

Mathematics
2 answers:
telo118 [61]3 years ago
6 0
A= a^2 = 6^2 = 36

answer  <span>D.
36 ft2</span>
Reil [10]3 years ago
4 0
Well, it is a square. So, from what we are given it is a 6ft by 6ft sandbox.
Area = base * height.

6*6 = 36
D, 36 ft2, would be your answer.

Hope this helps!
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AlekseyPX

9514 1404 393

Answer:

  B.

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Step-by-step explanation:

The function is of even degree with a negative leading coefficient. f(x) will tend toward negative infinity as x gets larger or smaller. That is ...

  • as x increases, f(x) decreases;
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<em>Even degree</em> means the end behaviors are the same for both large and small x. <em>Negative leading coefficient</em> means the function value decreases for larger x.

8 0
3 years ago
30 Points, 5 stars, thanks and Brainliest if answered correctly because I feel generous.
wlad13 [49]

Find the difference between each number:

-24/4 = -6

144/-24 = -6

The next number is multiplied by -6

You have the first 4 terms

5th term = -864 x -6 = 5184

6th term = 5184 x -6 = -31,104

7th term = -31,104 x -6 = 186,624

8th term = 186,624 x -6 = -1,119,744

4 0
3 years ago
Read 2 more answers
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Irina-Kira [14]

Given :

p = 0.68

margin of error, E = 0.1

99% confident interval

alpha, α = 1 - 0.99

             = 0.01

$\frac{\alpha }{2}=\frac{0.01}{2} = 0.005$

∴ $z_{\alpha/2}=z_{0.005}=2.5758$ (z-critical value)

Sample size = $z_{\alpha/2} \times \frac{p(1-p)}{E^2}$

                    $=(2.5758)^2 \times 0.68 \times \frac{(1-0.68)}{0.1^2}$

                    $= 6.63475 \times 0.68 \times \frac{0.32}{0.01}$

                   = 144.37

                  = 145 (rounded off)

Therefore, there are 145 businesses does she need to sample to meet this criteria.

6 0
3 years ago
Solve the system graphically<br> 1. x-2y=6 and 3x+2y=-6<br><br> 2. x-y=0 and 2x+3y=-5
zysi [14]

Step-by-step explanation:

1)The given equations are:

x − 2y = 6 ...(i)

3x − 6y = 0 ...(ii)

Putting x = 0 in equation (i) we get

=> 0 - 2y = 6

=> y = -3

x = 0, y = -3

Putting y = 0 in equation (i) we get

⇒x-2×0=6

⇒x=6

x = 6, y = 0

Use the following table to draw the graph

x 0 6

y -3 0

Plotting the two points A(0, -3) and B(6,0) equaion (1) can be drawn

Graph of the equation ..(ii)

3x - 6y = 0 ...(ii)

Putting x = 0 in equation (ii) we get

⇒3×0-6y=0

=> y = 0

x = 0, y = 0

Putting x = 2 in equation (2) we get

⇒3×2-6y=0

=> y = 1

x = 2, y = 1

Use the following table to draw the graph.

x 0 2

y 0 1

Draw the graph by plotting the two points O(0,0) and D(2,1) from table

We see that the two lines are parallel, so they won’t intersect

Hence there is no solution

2)

3 0
2 years ago
Simplify enter your answer
ioda
Answer: 5/14

Explanation:
19-14=5
3 0
2 years ago
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