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Fiesta28 [93]
3 years ago
5

There are 3 blouse and 2 pieces cloths for sale in the market. how many possible sets are there?​

Mathematics
1 answer:
Andrew [12]3 years ago
7 0

Answer:

Each item could be included in a set or not included. That gives 2^5 = 32 ways to choose sets, including 1 set with no items, 5 sets of 1 item, 10 sets of 2 items, 10 sets of 3 items, 5 sets of 4 items, and 1 set of 5 items.

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suppose river has new treats that are 10 calories each. how many of the new treats can she have and remain in her calorie range?
OlgaM077 [116]

She can have at least 3 and at most 6 dog treats in a day

7 0
3 years ago
Jenny spends $1.15 a day for lunch. Her cafeteria lunch account has a balance of $36.80. Write an equation that can be used to d
ExtremeBDS [4]

Answer:

Balance Divided By Lunch Cost

Step-by-step explanation:

Divide $36.80 by $1.15 to receive the answer 32. She can eat for 32 days.

4 0
3 years ago
Please helpppppp
creativ13 [48]

Let's first take a look at function G. From the first to second row, the x-value increases by 2, and the y-value increases by 8.

Thus, function G has a rate of change of 8/2, or 4.

In function H, there is a "2" before the "x", which means function H has a rate of change of 2.

Thus, the statement that is true is:

  • Function G has a rate of change of 4, and function H has a rate of change of 2

Let me know if you need any clarifications, thanks!

~ Padoru

8 0
3 years ago
Read 2 more answers
The slope of the line whose equation is 3 x - 2 y = 4 is:
olchik [2.2K]

Answer:

c 3/2

Step-by-step explanation:

3 0
4 years ago
A garden box has a perimeter of 18½ feet. If the length is 5 feet, what is the area of the garden box?
Travka [436]

Answer:

area=\frac{85}{4}feet^{2}

Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.

perimeter=18\frac{1}{2}\\\\length=5

2(length+width)=perimeter

Substitute,

2(5+width)=18\frac{1}{2}

Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

2(5+width)=\frac{37}{2}

Inverse operations,

2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

length=5\\\\width = \frac{17}{4}

length*width=area

Substitute,

5*\frac{17}{4}\\\\=\frac{85}{4}

area=\frac{85}{4}feet^{2}

4 0
3 years ago
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