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3 years ago

Given the functions f(×)=-×2+9 and g(×)=6-2×

Mathematics

1 answer:

lora16 [44]3 years ago

8 0

Answer:

hehe

Step-by-step explanation:

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What is the slope of the line through (-1,4) and (1,-2)

yawa3891 [41]

Answer:

-3

Step-by-step explanation:

Slope = change of x over change of y

6 over 2

line goes down so slope is negative

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3 years ago

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Casey went to the fabric store and bought 2 2/3 yards of yellow fabric, yards of purple fabric, 3 1/9 and a pair of 5 1/5 inch s

nasty-shy [4]

The answer is A: 5 7/9 yards

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3 years ago

State the horizontal asymptote of the rational function. f(x) = 3x^2 -4x -3/ 2x^2 - 3x+2

irina1246 [14]

Answer:

Step-by-step explanation:

$\displaystyle \lim_{x \to \infty} \dfrac{3x^2-4x-3}{2x^2-3x+2} =\dfrac{3}{2} \\$

Horizontal asymptote has for equation y=3/2

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3 years ago

Find the values of A, B, and C in the table.

PilotLPTM [1.2K]

Answer:

A = 1

B = 2

C = below

Step-by-step explanation:

Zero is included in the second interval, therefore, A = 1 is a correct choice (A must be also less than 2 ).

B must be positive, so that, f(0) is above the x-axis, therefore, B = 2 is a correct choice.

f(1.5) is negative, this means that the function is below the x-axis, then, C = below.

8 0

3 years ago

Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

$A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

The circumference of a quarter of circle is equal to

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

6 0

3 years ago