Average rate of change over [1,5] = f(5) - f(1) / 5 - 1
= [(17-5^2) - (17-1) ] / 4
= (-8 - 16) / 4 = -24 / 4 = -6 Answer
Answer: f would be 1 i think
Step-by-step explanation:
Answer:
I think f(0) = g(2) is the answer, I'm very sure.
Step-by-step explanation:
Answer:

Step-by-step explanation:

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