Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-
The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
Answer:
2.964
Step-by-step explanation:
Answer:
5
jk 4
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Since EF and GH are parallel lines then
∠EGF = ∠GFH = 60° ( Alternate angles )
Answer:
15 divided by 4 = 3 3/4
Step-by-step explanation:
First divide 15 on 4 to get 3.75. convert 3.75 to a fraction. 3 will stay as three, and 0.75 will be converted to 3/4. the answer to your question is 3 and 3/4. I hope this was correct. if it was then please mark as brainliest.
