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evablogger [386]

2 years ago

9

Find the measures of 21 and 22 80° 2102°

1 answer:

cestrela7 [59]2 years ago

4 0

Answer:

Angle 1 is 22°

Angle 2 is 78°

Step-by-step explanation:

Angles on a straight line always add up to 180°.

To find Angle 2, you would have to do 180° take away 102°.

180-102=78°

Angles in a triangle also add up to 180°.

So to find Angle 1, you would have to add the two Angles you already have and take it away from 180°.

80+78=158°

180-158=22°

Hope this helps :)

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Limit question: lim x-->pi ((e^sinx)-1)/(x-pi)

aleksandr82 [10.1K]

$\displaystyle\lim_{x\to\pi}\dfrac{e^{\sin x}-1}{x-\pi}$

Notice that if $f(x)=e^{\sin x}$ , then $f(\pi)=e^{\sin\pi}=e^0=1$ . Recall the definition of the derivative of a function $f(x)$ at a point $x=c$ :

$f'(c):=\displaystyle\lim_{x\to c}\frac{f(x)-f(c)}{x-c}$

So the value of this limit is exactly the value of the derivative of $f(x)=e^{\sin x}$ at $x=\pi$ .

You have

$f'(x)=\cos x\,e^{\sin x}\implies f'(\pi)=\cos\pi\,e^{\sin\pi}=-1$

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3 years ago

Let q(x)=8x-7 what is q(4) a. 25 b. 36 c. 39 d. 32

zhuklara [117]

I hope this helps you

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q (4)=32-7

q (4)=25

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3 years ago

Consider the diagram. What is the length of segment AB?

Sloan [31]

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3 years ago

Read 2 more answers

If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will

Tema [17]

Answer:

Hence after 3.98 sec i.e 4 sec Object will hit the ground .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object and it is given by ,

$R=v^2Sin$ (2Ф)/ $g$

Here R= range g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

$R=133^2*Sin(56)/31.36$

$R=14664.84/31.36$

$R=467.62$ fts

Now using Formula for time and range as

$R=VxT$

Vx is horizontal velocity

$Vx=V*cos$ Ф

$Vx=133*cos$ (28)

$Vx=117.43$ ft/sec

So above equation becomes as ,

$467.62=117.43*T$

$T=467.62/117.43$

$T=3.98 sec$

T is approximately equals to 4 sec.

4 0

3 years ago