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ad-work [718]
3 years ago
5

Helps me solve this problem please

Mathematics
1 answer:
NemiM [27]3 years ago
7 0
I’m pretty sure it’s the French and Indian war.
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b. You have saved $15,000 for a down payment. What is the max you can spend (max house price)? (4 points)
In-s [12.5K]

Answer:

maybe like 5k

Step-by-step explanation:

6 0
3 years ago
_16. Which expression is equivalent to
Phantasy [73]

Answer:

-2x-8

Step-by-step explanation:

1) Distribute:

-6/3x+-15/3-3

2) Simplify:

-2x-5-3

3) combine like terms:

-2x-8

hope this helps

5 0
3 years ago
[6+4=10 points] Problem 2. Suppose that there are k people in a party with the following PMF: • k = 5 with probability 1 4 • k =
kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is  = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = 1-\frac{_{n}^{12}\textrm{P}}{12^2}

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= \frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})

= 0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

6 0
3 years ago
Which is the constant term in the equation given in standard from 5x+3y=15
Alisiya [41]

Answer:

15

Step-by-step explanation:

The constant is the term without the variable

5x+3y=15

15 is the constant

4 0
3 years ago
Lou has an account with $10,000 which pays 6% interest compounded annually. If to that account, Lou deposits $5,000 at the begin
katovenus [111]

Answer:

Option d. $22154 is the right answer.

Step-by-step explanation:

To solve this question we will use the formula A=P(1+\frac{r}{n})^{nt}

In this formula A = amount after time t

                        P = principal amount

                        r = rate of interest

                       n = number of times interest gets compounded in a year

                        t = time

Now Lou has principal amount on the starting of first year = 10000+5000 = $15000

So for one year A=15000(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 15000(1+.06)^{1}

= 15000(1.06) = $15900

After one year Lou added $5000 in this amount and we have to calculate the final amount he got

Now principal amount becomes $15900 + $ 5000 = $20900

Then putting the values again in the formula

A=20900(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 20900(1+.06)^{1}

= 20900(1.06)=22154

So the final amount will be $22154.

3 0
3 years ago
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