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Mkey [24]
3 years ago
7

PLEASE I NEED HELP URGENTLLY, AND PLEASE SHOW WORK

Mathematics
1 answer:
kvasek [131]3 years ago
5 0

Answer:

Ok, so I say that the answer is 100

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If y = 3.2 when x = 1.6 find y when x = 19
faltersainse [42]
Thats easy
3.2/1.6=y/19

y=(3.2÷1.6)×19=38
8 0
3 years ago
And help on this one too.<br><br>THANKYOU!
Tpy6a [65]
For every ladybugs = +5 points
For every stinkbugs = -3 points

4 ladybugs and 8 stinkbugs in all

4(5) = 20
8(-3) = -24

20 - 24 = -4

The Players score is -4

hope this helps
5 0
3 years ago
A movie theater charges $5 for an adult’s ticket and $2 for a child’s ticket. one saturday, the theater sold 785 tickets for $32
laila [671]
They sold 570 adult tickets and 215 child tickets.
6 0
3 years ago
Read 2 more answers
Please solve this please​
ale4655 [162]

Answer:

C) \frac{2z+15}{6x-12y}

E) \frac{7d+5}{15d^2+14d+3}

F) \frac{-7a-b}{6b-4a}

Step-by-step explanation:

C)

One is given the following equation

\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}

In order to simplify fractions, one must convert the fractions to a common denominator. The common denominator is the least common multiple between the given denominators. Please note that the denominator is the number under the fraction bar of a fraction. In this case, the least common multiple of the denominators is (6x-12y). Multiply the numerator and denominator of each fraction by the respective value in order to convert the fraction's denominator to the least common multiple,

\frac{z+1}{x-2y}-\frac{2z-3}{2x-4y}+\frac{z}{3x-6y}

\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}

Simplify,

\frac{z+1}{x-2y}*\frac{6}{6}-\frac{2z-3}{2x-4y}*\frac{3}{3}+\frac{z}{3x-6y}*\frac{2}{2}

\frac{6z+6}{6x-12y}-\frac{6z-9}{6x-12y}+\frac{2z}{6x-12y}

\frac{(6z+6)-(6z-9)+(2z)}{6x-12y}

\frac{6z+6-6z+9+2z}{6x-12y}

\frac{2z+15}{6x-12y}

E)

In this case, one is given the problem that is as follows:

\frac{2}{3d+1}-\frac{1}{5d+3}

Use a similar strategy to solve this problem as used in part (c). Please note that in this case, the least common multiple of the two denominators is the product of the two denominators. In other words, the following value: ((3d+1)(5d+3))

\frac{2}{3d+1}-\frac{1}{5d+3}

\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}

Simplify,

\frac{2}{3d+1}*\frac{5d+3}{5d+3}-\frac{1}{5d+3}*\frac{3d+1}{3d+1}

\frac{2(5d+3)}{(3d+1)(5d+3)}-\frac{1(3d+1)}{(5d+3)(3d+1)}

\frac{10d+6}{(3d+1)(5d+3)}-\frac{3d+1}{(5d+3)(3d+1)}

\frac{(10d+6)-(3d+1)}{(3d+1)(5d+3)}

\frac{10d+6-3d-1}{(3d+1)(5d+3)}

\frac{7d+5}{(3d+1)(5d+3)}

\frac{7d+5}{15d^2+14d+3}

F)

The final problem one is given is the following:

\frac{3a}{2a-3b}-\frac{a+b}{6b-4a}

For this problem, one can use the same strategy to solve it as used in parts (c) and (e). The least common multiple of the two denominators is (6b-4a). Multiply the first fraction by a certain value to attain this denomaintor,

\frac{3a}{2a-3b}-\frac{a+b}{6b-4a}

\frac{3a}{2a-3b}*\frac{-2}{-2}-\frac{a+b}{6b-4a}

Simplify,

\frac{3a}{2a-3b}*\frac{-2}{-2}-\frac{a+b}{6b-4a}

\frac{-6a}{6b-4a}-\frac{a+b}{6b-4a}

\frac{(-6a)-(a+b)}{6b-4a}

\frac{-6a-a-b}{6b-4a}

\frac{-7a-b}{6b-4a}

4 0
3 years ago
Use the diagram to solve for the three variables so that the quadrilateral will be a rhombus. Show all of your work for full cre
satela [25.4K]

Answer:

  • x = 4
  • y = 4
  • z = 7

Step-by-step explanation:

Each triangle is a right triangle, and all are congruent. So ...

  90 -m∠CAB = (1/2)m∠CDA

  90 -(4x +33) = (1/2)(12x +34)

  57 -4x = 6x +17 . . . . . . . eliminate parentheses

  40 = 10x . . . . . . . . . . . . .add 4x-17

  4 = x

We also have ...

  2m∠CAD = m∠BCD

  2(3z +28) = 10z +28

  6z +56 = 10z +28 . . . . . eliminate parentheses

  28 = 4z . . . . . . . . . . . . . .subtract 6z+28

  7 = z . . . . . . . . . . . . . . . . divide by 4

Since BC = CD ...

  x = y = 4

The values of the three variables are ...

  x = 4, y = 4, z = 7.

3 0
3 years ago
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