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3 years ago

Find each of the following products a) 6x * (-2y) Answer ) -12xy

Mathematics

1 answer:

UNO [17]3 years ago

4 0

Step-by-step explanation:

<h2>6x × (-2y) = -12xy</h2><h2> thank you</h2>

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Which of the following numbers is greater than 7.03?

iren [92.7K]

Answer:

A:7.031

Step-by-step explanation:

both 7, but 7.031 has 031. 7.03 only has .03.

4 0

3 years ago

On the day Alexander was born, his father invested $5000in an account with a 1.2% annual growth rate. Write a function, A(t) tha

stepladder [879]

Answer:

Equation: $A(t)=5000(1.012)^n$

Worth more in 32 yr than in 17 yr by: $1199.92

Step-by-step explanation:

THe compound growth formula is:

$F=P(1+r)^n$

Where

F is the future amount (here, A(t))

P is the initial amount, here 5000

r is the rate of growth in decimal, 1.2% = 1.2/100 = 0.012

n is the time in years

Thus, we can say the function would be:

$A(t)=5000(1+0.012)^n\\A(t)=5000(1.012)^n$

Now, we want how much more it will be worth when 17 years and 32 years. We find the future amount, A(t), when n= 17 and n = 32 and find the difference. Shown below:

$A(t)=5000(1.012)^n\\A(17)=5000(1.012)^{17}\\=6124.05$

and

$A(32)=5000(1.012)^{32}\\=7323.97$

So, it will be worth more by:

7323.97 - 6124.05 = $1199.92

3 0

3 years ago

X= 2/3 y= 1/2 z=4 2/3 work out the value of z+x *y

Blizzard [7]

Answer: 16/9 or 1 7/9

Step-by-step explanation:

plug in the values

4 2/3 + 2/3 * 1/2

add the first two values

4 2/3 + 2/3 = 4 4/3 or 5 1/3

multiply 5 1/3 by 1/2

5 1/3 * 1/3 = 16/9 or 1 7/9

6 0

3 years ago

when seven is added to a certain number the result is the same as subtracting twice the number from sixteen what is the number .

jeyben [28]

The meaning of the question is

Let the unknown number be x

Therefore x+7=16-2x
Now 2x+x=16-7
3x=9
X=9/3
x=3

6 0

3 years ago

Find the first , fourth , and eighth terms of the sequence A(n) = -3 •2 ^x - 1

Usimov [2.4K]

Answer:

A(1) = -7

A(4) = -48

A(8) = -769

Step-by-step explanation:

$A(n) = -3.2 ^n - 1.....(1)\\\\Plug \: n= 1\: in \: (1)\\A(1) = -3.2 ^1 - 1 =-3.2-1= -6 -1 \\\huge\red{\boxed{A(1) = -7}}\\\\Plug \: n= 4\: in \: (1)\\A(4) = -3.2 ^4 - 1 =-3.16-1= -48 -1 \\\huge\purple{\boxed{A(4) = -49}}\\\\Plug \: n= 8\: in \: (1)\\A(8) = -3.2 ^8 - 1 =-3.256-1= -768 -1 \\\huge\orange{\boxed{A(8) = -769}}$

5 0

4 years ago