All categories

3 years ago

Does anyone know Experimental Probability?

1 answer:

7 0

If you roll a fair 6-sided die you can get 1, 2, 3, 4, 5 or 6. In total there are 6 possibilities for the outcomes. The theoretical probability to roll each number of 6 possible is the same and equal to 1/6.

If you roll a fair 6-sided die 600 times, you can expect that near 1/6 of these attempts will get you 3's. Then you expect about 600·1/6=100 3’s (you can't suppose to get exactly 100 3's, because the experimental probability may differ from theoretical).

Answer: correct choice is A.

You might be interested in

What percent of 96.4 is 23.4

Kipish [7]

Answer:

x = 24.27385%

Step-by-step explanation:

We can say 96.4x=23.4

Divide by 96.4: (x=23.4/96.4) = 0.24273858921

x=0.24273858921 so x = 24.27385...%

7 0

2 years ago

What number am i thinking of?<br> a. 21<br> b. 9<br> c. 69<br> d. 7

icang [17]

Your thinking of the number 69

6 0

3 years ago

You will need the same dataset used for problem 3 in homework 1 (the dataset obtained from the yahoo website with the company yo

stepladder [879]

Answer:

a) The probability of sampling at random a fish that is smaller in size than the value you would obtain by subtracting half the standard deviation from the average is 0.3085.

b) The probability of sampling at random a fish that is greater in size than the value you would obtain by adding half the standard deviation from the average is 0.3085.

c) The probability of sampling at random a fish that has a size between the two values is 0.383.

d) The 25th and 75 percentiles of fish size for the population using the normal distribution table is 5.69 and 5.87 respectively.

e) The probability that the average calculated will be less than the value is 0.3707.

Step-by-step explanation:

For the given data set mean $(\mu) = 5.75913$

Standard deviation $(\sigma) = 0.172229$

Variance $(\sigma2) = 0.0296$

Here we get is

$P(x < \mu - \sigma/2) = p(x < 5.673) \\\\ = 0.3085$

$P(x < \mu + \sigma/2) = p(x < 5.845) \\\\= 0.3085$

$P(\mu - \sigma/2 < x < \mu + \sigma/2) = p(5.673 < x < 5.845) \\\\= 0.383$

25th percentile:-

$= 25*[(n+1)/100]th term \\\\= 5.69$

75the percentile:-

$= 75*[(n+1)/100]th term\\\\ = 5.87$

$p(x < \mu - \sigma/3) = p(x < 5.7017) \\\\= 0.3707$

7 0

3 years ago

PLEASE HELP ME :(( i tried 12 as the answer and it’s wrong

AnnZ [28]

I think its 1/6

I'm not sure tho

u take the bottom and subtract it by the top then multiply

6 0

3 years ago

Read 2 more answers

A baseball team has home games on Friday and Sunday. The two games together earn $3532.50 for the team. Friday's game generate

Semmy [17]

First you would divide $3532.50 by 2 which would equal $1766.25.
The you would add $225.75 to $1766.25 which equals $1982.
The Friday had $1540.50 taken in & the Sunday game had $1982 taken in.

5 0

3 years ago