Answer:
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Since J is the midpoint of HK, that means HK is split into two sections HJ and JK that are the same length.
1) You are told that the m<span>easure of segment HJ = 9x-2 and that of segment JK = 4x+13. Since you also know they are equal lengths, you can set these equations equal to each other to find the value of x!
HJ = JK
</span>9x-2 = 4x+13
5x = 15
x = 3
2) Now you know x = 3. Plug that into your given equations for HJ and JK to find the length of each segment (or a shortcut would be to find one of them, and then you also know the other is the same length. I'm doing both, just to make sure I don't make a silly mistake!):
HJ = <span>9x-2
</span>HJ = 9(3) - 2
HJ = 27 - 2
HJ = 25
JK = 4x + 13
JK = 4(3) + 13
JK = 12 + 13
JK = 25
3) Finally, the length of HK is just the length of HJ + JK, or HK = 25 + 25 = 50.
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Answer: HJ = 25, JK = 25, HK = 50
The mean of the scores if 6 students in a competitive exam is 25 marks.
Given scores of 6 students are: 10,30,50,40,20 in a competitive exam.
We have to find out the mean of the mark of 6 students in a competitive exam.
Mean is the sum of all the values in a set of data, such as numbers, measurements, divided by the number of values. It is also known as average.
Mean=∑X/n
∑X=10+30+50+40+20
=150
N=6
Now to calculate the mean we have to divide 150 by number of students which is 6.
Mean=150/6
=25 marks.
Hence the mean of the scores of 6 students is 25 marks.
Learn more about mean at brainly.com/question/1136789
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Question is incomplete as it should include :
Marks of students =10,30,50,40,20.
Answer:
Step-by-step explanation:
H0: µ1 – µ2 = 0
HA: µ1 – µ2 ≠ 0
We have given,
The population variances are not known and cannot be assumed equal.
The test statistic for the test is
Where,
= sample meaan of population 1
= sample mean of population 2
= sample size of population 1
= sample size of population 2
Therefore, this is the test
