Say you have 7 divided by 3.5
7/3.5 If you set up like this 3.5 into 7, you move the decimal over once in 3.5
So you now have 35 into 7. Next you have to move the decimal on the seven however many times you moved the first decimal. So 7 is now 70
Next you just do simple division 35 into 70 =2
Step-by-step explanation:
P varies directly as the cubic root of Q means that:
![p = x \times \sqrt[3]{q}](https://tex.z-dn.net/?f=p%20%3D%20x%20%5Ctimes%20%20%5Csqrt%5B3%5D%7Bq%7D%20)
, where x is a real constant number.
Which means that:
![x = \frac{p}{ \sqrt[3]{q} }](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7Bp%7D%7B%20%5Csqrt%5B3%5D%7Bq%7D%20%7D%20)
for q ≠0.
So we get that for q=8,p=4 which means:
![x = \frac{4}{ \sqrt[3]{8} } = \frac{4}{2} = 2](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B4%7D%7B%20%5Csqrt%5B3%5D%7B8%7D%20%7D%20%20%3D%20%20%5Cfrac%7B4%7D%7B2%7D%20%20%3D%202)
As a result we get that for Q=64:
![p = 2 \times \sqrt[3]{64} = 2 \times 4 = 8 \\ since \: {4}^{3} = 4 \times 4 \times 4 = \\ 16 \times 4 = 64](https://tex.z-dn.net/?f=p%20%3D%202%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B64%7D%20%20%3D%202%20%5Ctimes%204%20%3D%208%20%5C%5C%20since%20%5C%3A%20%20%7B4%7D%5E%7B3%7D%20%20%3D%204%20%5Ctimes%204%20%5Ctimes%204%20%20%3D%20%20%5C%5C%20%2016%20%5Ctimes%204%20%3D%2064)
So for q=64,p=8.
We can use substitution or elimination
Let’s use substitution
Make slope intercept equation for the first equation
Y = -x + 5
Now plug in the y value for the second equation
-5x - 4(-x + 5) = -18
-5x + 4x - 20 = -18
-1x = 2, x = -2
There is one solution
