8,16,24,32,40,48,56,65,73,81,88.....
9,18,27,36,45,54,63,72,81,90....
since 81 is the smallest number in both lists, it is the LCM
When an ocluded front moves over farmland that has been in a drought then an extended period of rain happens. This beasically happens because <span>the cold air mass from the cold front meets the cool air that was ahead of the warm front. The warm air rises as these air masses come together.</span>
Answer:
−15
Step-by-step explanation:
9−6+5−3+6−2+8(4−7)
=3+5−3+6−2+8(4−7)
=3+2+6−2+8(4−7)
=3+2+4+8(4−7)
=3+6+8(4−7)
=9+8(4−7)
=9+(8)(−3)
=9+−24
=−15
9514 1404 393
Answer:
13 cm wide; 15 cm long
Step-by-step explanation:
Let w represent the original width. Then the original length is (w+2) and the original area is w(w+2). After the decrease, the width is (w-1) and the length is (w+1). The decreased area is (w-1)(w+1). The difference between these areas is 27, so we have ...
w(w+2) -(w-1)(w+1) = 27
w^2 +2w -(w^2 -1) = 27
2w +1 = 27
w = (27-1)/2 = 13
The original piece of cardboard was 13 cm wide and 15 cm long.
The height of the mountain estimated by two students is 2,467.98 meters.
<h3>
Height of the mountain </h3>
The height of the mountain is calculated as follows;
tanα = h/( a + b + x)
where;
- x is the distance between end of b and h
tan37 = h/(1850 + 740 + x)
tan37 = h/(2590 + x)
h = tan37(2590 + x)
h =1,951.82 + 0.7536x ---- (1)
tanβ = h/(b + x)
tan60 = h/(740 + x)
h = tan60(740 + x)
h = 1,281.68 + 1.732x ---- (2)
Solve (1) and (2) together
1,951.82 + 0.7536x = 1,281.68 + 1.732x
1,951.82 - 1,281.68 = 1.732x - 0.7536x
670.14 = 0.9784x
x = 684.93 m
h = 1,281.68 + 1.732x
h = 1,281.68 + 1.732(684.93)
h = 2,467.98 m
Thus, the height of the mountain estimated by two students is 2,467.98 meters.
Learn more about angle of elevation here: brainly.com/question/88158
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