Given:
The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).
To find:
The equation of the quadratic function.
Solution:
A quadratic function is defined as:
...(i)
It is passes through the point (0,11). So, substitute
in (i).


Putting
in (i), we get
...(ii)
The quadratic function passes through the point (5,31). So, substitute
in (ii).

Divide both sides by 5.
...(iii)
The quadratic function passes through the point (3,11). So, substitute
in (ii).
Divide both sides by 3.
...(iv)
Subtracting (iv) from (iii), we get




Putting
in (iv), we get



Putting
in (ii), we get
Therefore, the required quadratic equation is
.
Answer
I’m pretty sure it’s c
Explanation
Answer:
the pic is black send another one
Answer:
311/9
Step-by-step explanation:
trust me im big brain lol hope this helps
Answer:


And the best option would be:
4. Minimum: 869.69; maximum: 961.17
Step-by-step explanation:
We can assume that the variable of interst X is distributed with a binomial distribution and we can use the normal approximation.
For this case the mean would be given by:

And the standard deviation would be:

And if we find the limits we got:


And the best option would be:
4. Minimum: 869.69; maximum: 961.17