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Vera_Pavlovna [14]
4 years ago
11

Ed scored 8 goals for his soccer team this season. Javi scored 5 goals.

Mathematics
2 answers:
ch4aika [34]4 years ago
7 0
You add 8 and 5 so the equation would be 8+5=13
Colt1911 [192]4 years ago
6 0

Answer:

8+5=13

Step-by-step explanation:

Bc well Ed did 8 goals and Javi did 5 goals and 8+5+13

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7 – Зу = 20
nata0808 [166]

Answer:

x=1/15 y = -4 1/3

Step-by-step explanation:

First combine like terms.

-3y = 13

y= -13/3

y= -4 1/3

Substitute for y in next equation

-4 1/3 = 5x - 4

5x = 4 1/3 - 4

5x = 4 1/3 - 4

5x = 1/3

x = 1/3 divided by 5

Since fractions can't be divided, multiply by the inverse

x = 1/3 times 1/5 = 1/15

5 0
3 years ago
Please help ! I don’t understand:((
zysi [14]

Answer:

B

Step-by-step explanation:

sorry if im wrong but i used desmos next time its graphing use desmos

5 0
3 years ago
4/8 times 3/4 simplified pls and thank you
Ivahew [28]

Answer:

3/8

Step-by-step explanation:

divide out the 4's and you are left with 3/8

3 0
3 years ago
The parent function of a graph is f(x) = x2. The graph shifts a units to the left and down b units. Which function models the tr
Gnesinka [82]
<span>C) y = (x + a)2 - b </span>is the answer
8 0
3 years ago
Read 2 more answers
Help. I need help with these questions ( see image).<br> Please show workings.
Andrew [12]

9514 1404 393

Answer:

  4)  6x

  5)  2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

  \text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

  lim[h→0](f(x+h)-f(x))/h = 2ax +b

__

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

__

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0
3 years ago
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