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Rama09 [41]
3 years ago
13

Given m||n, find the value of x

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

17 =x

Step-by-step explanation:

These are alternate interior angles and alternate interior angles are equal when the lines are parallel

9x+7 = 10x-10

Subtract 9x from each side

9x+7-9x = 10x-10-9x

7 = x-10

Add 10 to each side

7+10 =x-10+10

17 =x

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A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
Question in image! Thanks for help.
irinina [24]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If the gradient of a line joining the points (-2, 6) and (5, b) is 14.<br> Find the value of b.
babunello [35]

Answer:

b = 104

Step-by-step explanation:

Slope is expressed as;

m = y2-y1/x2-x1

14 = b - 6/5-(-2)

14 = b - 6/5+2

14 = b-6/7

Cross multiply

b-6 = 14 * 7

b - 6 = 98

b  = 98 + 6

b = 104

3 0
3 years ago
Initially, there were only 86 weeds in the garden. The weeds grew at a rate of 29% each week. The following function represents
Dmitry [639]

Answer:

Option A. f(x)=86[1.04]^{x} ; grows approximately at a rate of 0.4% daily

Step-by-step explanation:

we have

f(x)=86(1.29)^{x}

where

f(x) the number of weeds in the garden

x ----> the number of weeks

Calculate how quickly the weeds grow each day

Remember that a week is equal to seven days

so

f(x)=86(1.29)^{\frac{x}{7}}

Using the law of exponents

b^(x/a) = b^(x*(1/a)) = (b^(1/a))^x

so

f(x)=86[(1.29)^{\frac{1}{7}}]^{x}

f(x)=86[1.04]^{x}

therefore

The rate is approximately

1.04=1+r

r=1.04-1=0.04=4% daily

8 0
3 years ago
Pls Find the value of x
tatiyna

x + 104 + 28 = 180  \\ (140 + 28 = 132) \\ x = 132

3 0
3 years ago
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