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UkoKoshka [18]
3 years ago
6

Evaluate each using the values given. m-((-3) + p)-q; use m= 10, p=-6, and q = 10

Mathematics
1 answer:
Keith_Richards [23]3 years ago
4 0

Answer:

9

Step-by-step explanation:

10-((-3) + -6)-10

10-(-9)-10

10+9-10

9

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20 points
irinina [24]

Answer:

(a) 9x^2+16x-4

(b) 9a(2a+5)

(c) (y-6)(y-4)

Step-by-step explanation:

(a)

(9x-2)(x+2)=

9x^2-2x+18x-4=

9x^2+16x-4

(b)

18a^2+45a=

9a(2a+5)

(c)

y^2-10y+24=

(y-6)(y-4)

Hope this helps!

4 0
2 years ago
Help pleaseeee thank you
nadezda [96]

Answer its 24x8

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Determine if the following functions are inverses of each other:
Alenkasestr [34]

Answer:

both outputs are x so f(x) and g(x) are inverses of each other

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How many groups of 1/2 days are in 1 week? Write a multiplication equation or a division equation to represent the question, the
worty [1.4K]

Answer:

14 groups

Step-by-step explanation:

Given

Groupings = \frac{1}{2}\ day

Duration = 1\ week

Required

Determine the number of group in the week

To do this, we simply divide the duration by the number half day group.

This gives:

Group = \frac{Duration}{Groupings}

Group = \frac{1\ week}{1/2\ days}

Convert week to days

Group = \frac{7\ days}{1/2\ days}

Group = \frac{7}{1/2}

Group = 7 / \frac{1}{2}

Convert to multiplication

Group = 7 * \frac{2}{1}

Group = \frac{14}{1}

Group = 14

<em>Hence, there are 14 groups</em>

4 0
3 years ago
Suppose a continuous probability distribution has an average of μ=35 and a standard deviation of σ=16. Draw 100 times at random
yulyashka [42]

Answer:

To use a Normal distribution to approximate the chance the sum total will be between 3000 and 4000 (inclusive), we use the area from a lower bound of 3000 to an upper bound of 4000 under a Normal curve with its center (average) at 3500 and a spread (standard deviation) of 160 . The estimated probability is 99.82%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we have that the mean is \mu*n and the standard deviation is s = \sigma \sqrt{n}

In this problem, we have that:

\mu = 100*35 = 3500, \sigma = \sqrt{100}*16 = 160

This probability is the pvalue of Z when X = 4000 subtracted by the pvalue of Z when X = 3000.

X = 4000

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{4000 - 3500}{160}

Z = 3.13

Z = 3.13 has a pvalue of 0.9991

X = 3000

Z = \frac{X - \mu}{s}

Z = \frac{3000 - 3500}{160}

Z = -3.13

Z = -3.13 has a pvalue of 0.0009

0.9991 - 0.0009 = 0.9982

So the correct answer is:

To use a Normal distribution to approximate the chance the sum total will be between 3000 and 4000 (inclusive), we use the area from a lower bound of 3000 to an upper bound of 4000 under a Normal curve with its center (average) at 3500 and a spread (standard deviation) of 160 . The estimated probability is 99.82%.

5 0
3 years ago
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