6785 - 6496 = 289 units
289 x 13p = 3757p
3757p = £37.57
37.57 + 21.45 = £59.02
Answer:
THE DISTANCE OF SUB IS 5892480000000IN
1MI=63630 IN
930000000MI=93000000×63360 IN=589248000000IN
X=NUMBER OF FIREFLIES
X=0.4IN=5892480000000IN
X=58924800000000IN×0.4IN
X=147312000000000
csc(2x) = csc(x)/(2cos(x))
1/(sin(2x)) = csc(x)/(2cos(x))
1/(2*sin(x)*cos(x)) = csc(x)/(2cos(x))
(1/sin(x))*1/(2*cos(x)) = csc(x)/(2cos(x))
csc(x)*1/(2*cos(x)) = csc(x)/(2cos(x))
csc(x)/(2*cos(x)) = csc(x)/(2cos(x))
The identity is confirmed. Notice how I only altered the left hand side (LHS) keeping the right hand side (RHS) the same each time.
Answer:
g(x) = -2|x+1| -3
Step-by-step explanation:
f(x) = |x|
y = f(x) + C C < 0 moves it down
y = |x| -3 for shifting down 3
y = f(x + C) C > 0 moves it left
y = |x+1| -3 for move it left 1
y = Cf(x) C > 1 stretches it in the y-direction
y = 2|x+1| -3 to stretch it 2 vertically
y = −f(x) Reflects it about x-axis
y = -2|x+1| -3
The correct answer is D.
The area is base x height which in this case is 14 x 8 = 112 which is answer choice D.
Hope this helps.
