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kumpel [21]
3 years ago
6

you invest $1600 into an account that pays an interest rate of 4.75 percent compounded continuously. Calculate the balance after

seven years.
Mathematics
1 answer:
BigorU [14]3 years ago
5 0
Compounding continuously uses the A = Pe^(rt) formula
A = amount in the account after specified period of time
P = principal
e = constant 
r = rate (change to decimal)
t = time in years 
A = 1600<em>e</em>^(.0475*7)
A = $ 2231.12

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Answer:

42 days

Step-by-step explanation:

1 week equals 7 days

7 × 6 = 42

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Hurry please!!
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Answer:

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Driving at a constant speed, Reggie travels 300 kilometers in 1 hour.
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Evaluate the following
IRINA_888 [86]

(a) [\frac{9}{2.6}  - \frac{2.5^{2} }{2.5} ]^{2}

Answer:

[\frac{9}{2.6}  - \frac{2.5^{2} }{2.5} ]^{2}

= [\frac{9}{2.6}  - \frac{2.5*2.5 }{2.5} ]^{2}

= [\frac{9}{2.6}  - \frac{2.5}{1} ]^{2}

*canceling 2.5 in numerator and denominator*

= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) [[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}    ] ^{2}

Answer:

[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\

*using [x^{a}]^b = x^{ab}*

= [\frac{3x^{3a}y^{3b}} {-3x^{3a} y^{3b} }] ^{2}        

*Again, using [x^{a}]^b = x^{ab}*

= \frac{3x^{2*3a}y^{2*3b}} {-3x^{2*3a} y^{2*3b} }  \\= (-1)\frac{3x^{6a}y^{6b}} {3x^{6a} y^{6b} }\\[\tex]*taking -1 common, denominator and numerator are equal*[tex]= -(1)\frac{1}{1}\\= -1

Property used: 'Power of a power'

We can raise a power to a power

(x^2)4=(x⋅x)⋅(x⋅x)⋅(x⋅x)⋅(x⋅x)=x^8

This is called the power of a power property and says that to find a power of a power you just have to multiply the exponents.

3 0
3 years ago
If you subtract 426 from 913 how many times would you need to regroup? and how can you tell?
Eduardwww [97]
I need -487 time to regroup. i did 426 - 913 = -487
5 0
3 years ago
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