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kumpel [21]
3 years ago
6

you invest $1600 into an account that pays an interest rate of 4.75 percent compounded continuously. Calculate the balance after

seven years.
Mathematics
1 answer:
BigorU [14]3 years ago
5 0
Compounding continuously uses the A = Pe^(rt) formula
A = amount in the account after specified period of time
P = principal
e = constant 
r = rate (change to decimal)
t = time in years 
A = 1600<em>e</em>^(.0475*7)
A = $ 2231.12

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Find the absolute maximum and minimum values of f(x, y) = x+y+ p 1 − x 2 − y 2 on the quarter disc {(x, y) | x ≥ 0, y ≥ 0, x2 +
Andreas93 [3]

Answer:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

Step-by-step explanation:

In order to find the absolute max and min, we need to analyse the region inside the quarter disc and the region at the limit of the disc:

<u>Region inside the quarter disc:</u>

There could be Minimums and Maximums, if:

∇f(x,y)=(0,0) (gradient)

we develop:

(1-2x, 1-2y)=(0,0)

x=1/2

y=1/2

Critic point P(1/2,1/2) is inside the quarter disc.

f(P)=1/2+1/2+p1-1/4-1/4=1/2+p1

f(0,0)=p1

We see that:

f(P)>f(0,0), then P(1/2,1/2) is a maximum relative

<u>Region at the limit of the disc:</u>

We use the Method of Lagrange Multipliers, when we need to find a max o min from a f(x,y) subject to a constraint g(x,y); g(x,y)=K (constant). In our case the constraint are the curves of the quarter disc:

g1(x, y)=x^2+y^2=1

g2(x, y)=x=0

g3(x, y)=y=0

We can obtain the critical points (maximums and minimums) subject to the constraint by solving the system of equations:

∇f(x,y)=λ∇g(x,y) ; (gradient)

g(x,y)=K

<u>Analyse in g2:</u>

x=0;

1-2y=0;

y=1/2

Q(0,1/2) critical point

f(Q)=1/4+p1

We do the same reflexion as for P. Q is a maximum relative

<u>Analyse in g3:</u>

y=0;

1-2x=0;

x=1/2

R(1/2,0) critical point

f(R)=1/4+p1

We do the same reflexion as for P. R is a maximum relative

<u>Analyse in g1:</u>

(1-2x, 1-2y)=λ(2x,2y)

x^2+y^2=1

Developing:

x=1/(2λ+2)

y=1/(2λ+2)

x^2+y^2=1

So:

(1/(2λ+2))^2+(1/(2λ+2))^2=1

\lambda_{1}=\sqrt{1/2}*-1 =-0.29

\lambda_{2}=-\sqrt{1/2}*-1 =-1.71

\lambda_{2} give us (x,y) values negatives, outside the region, so we do not take it in account

For \lambda_{1}: S(x,y)=(0.70, 070)

and

f(S)=0.70+0.70+p1-0.70^2-0.70^2=0.42+p1

We do the same reflexion as for P. S is a maximum relative

<u>Points limits between g1, g2 y g3</u>

we need also to analyse the points limits between g1, g2 y g3, that means U(0,0), V(1,0), W(0,1)

f(U)=p1

f(V)=p1

f(W)=p1

We can see that this 3 points are minimums relatives.

<u>Conclusion:</u>

We compare all the critical points P,Q,R,S,T,U,V,W an their respective values f(x,y). We find that:

absolute max: f(x,y)=1/2+p1 ; at P(1/2,1/2)

absolute min: f(x,y)=p1 ; at U(0,0), V(1,0) and W(0,1)

4 0
3 years ago
What set of reflections would carry triangle ABC onto itself?
Natalija [7]

Answer:

B

Step-by-step explanation:

A is on the x axis

B is on the y axis

C is on the x axis

5 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLY,5 STARS,AND THANK<br><br> 320/40 = 32 tens / 4 tens
victus00 [196]

Answer:

320/4=8   8 tens /4 tens =2

Step-by-step explanation:

7 0
3 years ago
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The product of 3 consecutive odd numbers is 2,145. Enter a simplified expression for finding the numbers. Let n be the first odd
Arlecino [84]

Answer:

11, 13 and 15.

Step-by-step explanation:

Let's say that the odd number is "x". If x is for example 15, then the next ODD number would be 15+2=17 and the one after that would be 15+2+2=15+4=19.

Applying that here, we get:

Odd number* the next odd number*the next odd number=2145

x*(x+2)*(x+4)=2145

x*(x^2+4x+2x+8)=2145

x^3+6x^2+8x=2145

By solving the polynomial, you get x=11.

Which makes our three numbers: 11, 13 and 15.

11*13*15=2145. The answer checks.

6 0
3 years ago
How long a rope is required to reach from the top of a building 40 feet high 30 feet from the base of the building?
Goshia [24]
70 feet.
If you're 30 feet from the base, then you have to climb that 30 feet, plus the 40 foot length of that building. (:

7 0
3 years ago
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