1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vlada-n [284]
3 years ago
6

Maria has 3 more than twice as many crayons as Elizabeth. How many crayons does Maria have? C = crayons 2C + 3 3C + 2 3 + 2 + c

pless help​
Mathematics
1 answer:
nadya68 [22]3 years ago
5 0
Hello,

twice as many means that the number of crayons is multiplied by 2, which would give 2C
she also has 3 more than that so you would add 3 (+3)
this would give you the expression 2C+3

hope this helped :)
You might be interested in
Solve for b.<br> 7<br> b<br> 12<br> b= ✓ [?]<br> Pythagorean Theorem: a2 + b2 = c2<br> Enter
fomenos

Answer: b=\sqrt{95}

Step-by-step explanation:

To solve for b, we want to use the Pythagorean Theorem as given.

b and 7 are the legs, and 12 is the hypotenuse.

7^2+b^2=12^2      [exponent]

49+b^2=144     [subtract both sides by 49]

b^2=95               [square root both sides]

b=\sqrt{95}

Now we know b=\sqrt{95}.

6 0
3 years ago
Which number is greatest?
raketka [301]
A) =27.2
b) = 30.1
c) =31.2
d) =36.6

answer = D
8 0
3 years ago
Read 2 more answers
Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

6 0
3 years ago
the sum of two numbers is 67 if three times the smaller number is subtracted by the larger the result is 7, find two numbers
just olya [345]
Um I think it's 3x7x4=81 or like this 40+20+7=67.
3 0
3 years ago
Read 2 more answers
Need help with these 2 questions ASAP, no links and a answer with an explanation will get brainly
marin [14]

Answer:

Yes, Fiona is correct

Step-by-step explanation:

WHen the pythagorean theorem is applied to the side lengths (2^2 + 4^2 = c^2), the result for c^2 is 20. The correct answer would be sqrt.20. But Fiona is also correct becuase sqrt of 20 can be simplified to sqrt.4 * sqrt.5; which equals 2*sqrt.5

3 0
3 years ago
Read 2 more answers
Other questions:
  • Consider the following.
    8·1 answer
  • Simplify 42-7-2-3-2-(1 point)<br> 218<br> -<br> 812<br> 68
    15·2 answers
  • Hey need help asap! Can you please find the ending solution to this
    13·1 answer
  • I can't solve this I need help??? ​
    8·2 answers
  • Given P(1,3) and Q(3,7) what is the slope of PQ
    11·1 answer
  • If Anna can run 2km in 8 min, how long will it take her to run 5 km if she maintains her speed​
    11·1 answer
  • If f(x)=x²-16 is continuous at x = -4, find f(-4).
    7·2 answers
  • A card game requires that you have a sum of 5 in order to win. Based on the cards shown below, will Cameron win the game? Look a
    10·1 answer
  • Can somebody solve this x/15=8
    14·1 answer
  • Please help I’ll give Brainiest
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!