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2 years ago

Helps me plz a=8, b=15, c=

Mathematics

2 answers:

n200080 [17]2 years ago

8 0

Answer:

Step-by-step explanation:

I think its c

netineya [11]2 years ago

3 0

Answer:

c^2=a^2+b^2

c^2= 8^2+15^2

c^2=64+225

c=√289

c=17

thanks

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If pqr = 1 , rst = 0 , and spr = 0, which of the following must be zero?

ahrayia [7]

P,Q,R can't be 0, because their product is nonzero. Either of S and T could be 0, but the third one only works if S is 0.

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3 years ago

Consider the compound inequality x < 4 and x>a. If a=4 and the compounding word were "or" instead of "and",what would the

FinnZ [79.3K]

Answer:

We have:

x < 4 AND x > a.

if a = 4 and we use an "or" instead of the "and" we have:

x < 4 or x > 4.

This is:

"x is larger than 4 or smaller than 4."

Then the solution of this is all the real numbers except the value x = 4.

The set of solutions can be written as:

{xI x ∈ R \ [4]}

Where this reads:

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Or we also could write it as:

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3 years ago

Solve the equation 58 - 10x ≤ 20 + 9x

drek231 [11]

Answer:

x≥2

Step-by-step explanation:

First, write out the equation as you have it:

$58-10x\leq20+9x$

Then, add $10x$ to both sides:

$58-10x+10x\leq20+9x+10x\\58\leq20+19x$

Next, subtract $20$ from both sides:

$58-20\leq20-20+19x\\38\leq19x$

Finally, divide both sides by $19$ :

$\frac{38}{19}\leq\frac{19x}{19}\\2\leq x$

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3 years ago

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3 years ago

A study sampled 350 upperclassmen (Group 1) and 250 underclassmen (Group 2) at high schools around the city of Houston. The stud

iris [78.8K]

Answer:

$-0.048$

Do not reject $H_0:P_1-P_2=0$

Step-by-step explanation:

From the question we are told that

Sample size $n_1=350$

Sample size $n_2=250$

Sample proportion 1 $\hat P= \frac{25}{350} =>0.07$

Sample proportion 2 $\hat P= \frac{19}{250} =>0.076$

95% confidence interval

Generally for 95% confidence level

Level of significance

$\alpha = 1-0.95=>0.05$

$\alpha /2=\frac{0.05}{2} =>0.025$

Therefore

$Z_a_/_2=1.96$

Generally the equation for confidence interval between $P_1 - P_2$ is mathematically given as

$(\hat P_1-\hat P_2)\pm Z_a_/_2\sqrt{\frac{\hat P_1(1-\hat P_1)}{n_1}+\frac{\hat P_2(1-\hat P_2)}{n_2} }$

$(0.07-0.076)\pm 1.96\sqrt{\frac{0.07(1-0.07)}{350}+\frac{0.076(1-0.076)}{250} }$

$(0.07-0.076)\pm 1.96\sqrt{4.66896*10^-^4 }$

$(-0.006)\pm 0.042$

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$(-0.006)+ 0.042=>0.036$

Therefore

Confidence interval is

$-0.048$

Conclusion

Given the confidence interval has zero

Therefore do not reject $H_0:P_1-P_2=0$

6 0

2 years ago