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BartSMP [9]
2 years ago
6

Select all the expressions that are equivalent to 310 3 – 5 .

Mathematics
1 answer:
sukhopar [10]2 years ago
8 0

Answer:

I don´t know how to help

Step-by-step explanation:

There are no choices

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Pi need help like right now
ValentinkaMS [17]
Irrational numbers are nonrepeating decimals like 0.1257486...

sqrt(150) is irrational gives nonrepeating decimal

12^2 = 144

sqrt(625) = 25

sqrt(49) .. sqrt(50) .. sqrt(64)
7 .. sqrt(50) .. 8
in between 7 and 8
3 0
3 years ago
An urn contains nine red and one blue balls. A second urn contains one red and five blue balls. One ball is removed from each ur
il63 [147K]

Answer:

0.362

Step-by-step explanation:

When drawing randomly from the 1st and 2nd urn, 4 case scenarios may happen:

- Red ball is drawn from the 1st urn with a probability of 9/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this case to happen is (9/10)*(1/6) = 9/60 = 3/20 or 0.15. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 5 blue)/(8 red + 1 blue + 5 blue) = 6/14 = 3/7.

- Red ball is drawn from the 1st urn with a probability of 9/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (9/10)*(5/6) = 45/60 = 3/4 or 0.75. The probability that a ball drawn randomly from the third urn is blue given this scenario is (1 blue + 4 blue)/(8 red + 1 blue + 1 red + 4 blue) = 5/14

- Blue ball is drawn from the 1st urn with a probability of 1/10, blue ball is drawn from the 2nd urn with a probability of 5/6. The probability of this event to happen is (1/10)*(5/6) = 5/60 = 1/12. The probability that a ball drawn randomly from the third urn is blue given this scenario is (4 blue)/(9 red + 1 red + 4 blue) = 4/14 = 2/7

- Blue ball is drawn from the 1st urn with a probability of 1/10, red ball is drawn from the 2st urn with a probability of 1/6. The probability of this event to happen is (1/10)*(1/6) = 1/60. The probability that a ball drawn randomly from the third urn is blue given this scenario is (5 blue)/(9 red + 5 blue) = 5/14.

Overall, the total probability that a ball drawn randomly from the third urn is blue is the sum of product of each scenario to happen with their respective given probability

P = 0.15(3/7) + 0.75(5/14) + (1/12)*(2/7) + (1/60)*(5/14) = 0.362

8 0
3 years ago
Which system of equations has the same solution as the one above ?
Ber [7]

Answer:

x+4y=-35

-8x-4y=28

Step-by-step explanation:

The answer to the original equations is (1, -9). You can solve that by using substitution by moving the 4y over and substituting that equation for x on the second part of the top equation. Using elimination, the second set of answers will give you the same, (1, -9)!

7 0
3 years ago
Help pleaseeeeeeeeee
Margaret [11]

Answer:

24

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
The product of a number and four is subtracted from three to give forty-<br> seven
ValentinkaMS [17]

Answer:

47=4n-3

Step-by-step explanation:

N=11 btw

5 0
3 years ago
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