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2 years ago

51: Y = 3: 5 value of Y

Mathematics

2 answers:

VashaNatasha [74]2 years ago

8 0

Answer:

Step-by-step explanation:

<h3>51 : Y = 3 : 5</h3><h3 /><h3>51 ÷ <u>17</u> = 3</h3><h3 /><h3>•To find the Y we should multiply 5 by 17</h3><h3 /><h3> 5 × 17 = 85</h3><h3 /><h3>51 : <u>85</u> = 3 : 5</h3><h3 /><h3>•Checking</h3><h3 /><h3>51 ÷ 17 = 3 ; 85 ÷ 17 = 5</h3><h3 />

$\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}$

ivann1987 [24]2 years ago

7 0

Answer:Y=25:3

Step-by-step explanation:

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. A population of rabbits oscillates 25 above and below an average of 129 during the year, hitting the lowest value in January (

Burka [1]

Answer:

Because we know that here we have an oscillation, we can model this with a sine or cosine function.

P = A*cos(k*t) + M

where:

k is the frequency

A is the amplitude

M is the midline

We know that at t = 0, we have the lowest population.

We know that the mean is 129, so this is the midline.

We know that the population oscillates 25 above and below this midline,

And we know that for t = 0 we have the lowest population, so:

P = A*cos(k*0) + 129 = 129 - 25

P = A + 129 = 129 - 25

A = -25

So, for now, our equation is

P = -25*cos(k*t) + 129

Because this is a yearly period, we should expect to see the same thing for t = 12 (because there are 12 months in one year).

And remember that the period of a cosine function is 2*pi

Then:

k*12 = 2*pi

k = (2*pi)/12 = pi/6

Finally, the equation is:

P = -25*cos(t*pi/6) + 129

Now we want to find the lowest population was in April instead:

if January is t = 0, then:

February is t = 2

March is t = 3

April is t = 4

Then we would have that the minimum is at t = 4

If we want to still use a cosine equation, we need to use a phase p, such that now our equation is:

P = -25*cos(k*t + p) + 129

Such that:

cos(k*4 + p) = 1

Then:

k*4 + p = 0

p = -k*4

So our equation now is:

P = -25*cos(k*t - 4*k) + 129

And for the periodicity, after 12 months, in t = 4 + 12 = 16, we should have the same population.

Then, also remembering that the period of the cosine function is 2*pi:

k*12 - 4*k = 2*pi

k*8 = 2*pi

k = 2*pi/8 = pi/4

And remember that we got:

p = -4*k = -4*(pi/4) = -pi

Then the equation for the population in this case is:

P = -25*cos( t*pi/4 - pi) + 129

7 0

2 years ago

What is the answer to 2/3 1/8 1/12?

Anna71 [15]

Your question seem to me non-understandable. Are they adding up together ?
or multiplying ?

5 0

3 years ago

Simplify:<br><br> -i^2 radical -96

Doss [256]

Simplify by combining the real and imaginary parts of each expression.

1 , − 96

3 0

3 years ago

The Candela brothers own two pizza restaurants, one on Park Street and one on Bridge Road.

koban [17]

The mean, median and mode are measures of central tendency, that is they tend to indicate the location middle of the data

Required values;

(a) The performance for the week for Park Street

Revenue is <u>Q₂ < $7,500 < Q₃</u>

The sales for the week is better than <u>72.91%</u> of all sales

The performance for the week for Bridge Road

Revenue; <u>Q₂ < $7,100 < Q₃</u>

The sale for the week is better than <u>59.87%</u> of all sales

(b) The mean is <u>$3611</u>

The median is $<u>3,600</u>

The standard deviation is $<u>3250</u>

The Interquartile range is $<u>6075</u>

Reason:

The table of values that maybe used to find a solution to the question is given as follows;

$\begin{array}{|l|l|l|}\mathbf{Variable} &\mathbf{Park}&\mathbf{Bridge}\\N&36&40\\Mean&6611&5989\\SE \ Mean&597&299\\StDev&3580&1794\\Minimum&800&1800\\Q_1&3600&5225\\Median&6600&6000\\Q_3&9675&7625\\Maximum&14100&8600\end{array}\right]$

(a) Park Street revenue = $7,500

Bridge Road's revenue = $7,100

The two stores sold close to but below the 75th percentile

Bridge Road revenue;

The z-score is given as follows;

$Z = \dfrac{x - \mu }{\sigma }$

$Z = \dfrac{7100 - 5,989 }{1794 } \approx 0.6193$

From the Z-Table, we have;

The percentile= 0.7291

Therefore, the sale for the week for Park Street is better than <u>72.91%</u> of all the sales

Park Street revenue;

The z-score is given as follows;

$Z = \dfrac{7500 - 6611}{3580} \approx 0.25$

From the Z-Table, we have;

The percentile = <u>0.5987</u>

Therefore, the sale for the week is better than <u>59.87 %</u> of all the sales

(b) Given that the operating cost is $3,000, frim which we have;

The subtracted value is subtracted from the mean and median to find the new value

Profit = The revenue - Cost

New mean = 6611 - 3000 = 3611

The new mean = <u>$3,611</u>

The new median = 6600 - 3000 = 3600

The new median = <u>$3,600</u>

The standard deviation and the interquartile range remain the same, therefore, we have;

The standard deviation = <u>$3,580</u>

The interquartile range = 9675 - 3600 = 6075

The interquartile range = <u>6075</u>

Learn more here:

brainly.com/question/21133077

brainly.com/question/23305909

5 0

2 years ago

An elevator goes up to seven floor it travels down five floors from there it goes up three floors write a sum of integers that c

SIZIF [17.4K]

7-5+3=5
The elevator is on level five

6 0

1 year ago

51: Y = 3: 5 value of Y​

51: Y = 3: 5 value of Y