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2 years ago

6

Help I’m struggling badly in math

1 answer:

Fynjy0 [20]2 years ago

5 0

Answer:

bran to blueberry: 4:1

banana nut to bran: 1 to 2

total to corn: 12 muffins to 5 muffins

bran to total: 1/3

Step-by-step explanation:

hope that helped.

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A bag contains 20 marvels of the same size for blue green and red the probability of picking a blue marbles 20% probability of p

strojnjashka [21]

Answer:

30% chance of picking a red marble

Step-by-step explanation:

since 70% of the bag is filled with blue or green marbles the rest of the bag (100-70=30) is the percent of red marbles.

6 0

3 years ago

Find the first fourth and eighth terms of A(n)=-2•5^n-1

Mila [183]

The first term is 0. The fourth is 1000. The eighth term is 10,000,000. All you have to do is plug the term you want to find into n and then solve.

5 0

3 years ago

What is the slope of the line shown below?

melisa1 [442]

Answer:

C. 2

Step-by-step explanation:

Gradient = $\frac{change in y}{change in x}$

Gradient = $\frac{6}{3}$

Gradient = 2

7 0

2 years ago

Read 2 more answers

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago

Raymond drove from San Antonio to Dallas in 5.2 Hours. It is 390miles from San Antonio to Dallas. If Raymond drove at a constant

Aleonysh [2.5K]

Answer:

75mph

calculated it

3 0

3 years ago

Read 2 more answers