All categories

2 years ago

We need a minimum of 30 book sales by today. If 10 books were sold yesterday, what are the possible numbers for sales today

1 answer:

amm18122 years ago

6 0

I mean it would be A and D because I don't know why they are both the same answer. If 10 books were sold yesterday, at LEAST 20 are needed to make the goal.

You might be interested in

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

2 years ago

Allen has a photo that is 6in by 8in what will the dimension of the photo be if he scales it down by a factor of 1\2

lesantik [10]

A photo of 6 and 8 is scaled down to 1/2 the size
To find this, you multiply both by 1/2 or divide by 2
The new dimensions are 3 by 4
6 divided by 2=3
8 divided by 2=4

6 0

2 years ago

BRAINLIST AND 20 POINTS I REALLY NEED HELP ASAP (10 POINTS FOR EACH QUESTION)

antoniya [11.8K]

Answer:

7 bottles

$10

Step-by-step explanation:

multiply

1/6×42= 7 bottles

5/9×18= $10

8 0

3 years ago

Which line segment is drawn in the figure? w DYZ WY XZ I wz

maksim [4K]

Answer:

Step-by-step explanation:

X and Z are points so that makes 2 endpoints, and a line segment

4 0

3 years ago

7 Solve the equation x^2 - 8x + 15 = 0.

Oksanka [162]

Answer:

x=5 x=3

Step-by-step explanation:

x^2 - 8x + 15 = 0

Factor

What 2 numbers multiply to 15 and add to -8

-5*-3 = 15

-5-3 = -8

(x-5)(x-3) =0

Using the zero product property

x-5 =0 x-3 =0

x=5 x=3

3 0

3 years ago

Read 2 more answers