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lubasha [3.4K]
3 years ago
5

Solve the following equation. Show your work. x 2 - 4 = 0

Mathematics
1 answer:
n200080 [17]3 years ago
4 0

Answer:

-4 sorry if not right i had this question before

Step-by-step explanation:

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Hector is flying a kite. He has let out 86 feet
Kaylis [27]

Answer:

Hector's kite is 61.84 feet from the ground.

Step-by-step explanation:

The angle of elevation of the kite is 42°15’30” when converted to decimals, it is 42.258333^{0} ≅ 42.26^{0}

Let the height of the kite to the horizontal of angle of elevation be represented as x. Applying the trigonometric function to the sketch of Hector's kite,

Sin θ = \frac{opposite}{hypotenus}

Sin 42.26^{0} = \frac{x}{86}

⇒ x = 86 x Sin 42.26^{0}

      = 86 x 0.6725

     = 57.835

x ≅ 57.84 feet

The height of Hector's kite from the ground = x + 4

                                    = 57.84 + 4

                                   = 61.84 feet

7 0
3 years ago
Peter has changed his diet to eat healthier. 2/3 of his meals are gluten free and of those gluten free meals 1/2 are vegan. How
vfiekz [6]
1 1/2 of his total diet in gluten free and vegan
4 0
2 years ago
Write an equation in slope intercept form for the line thepasses through (-1,-6) and is parallel to x+3y=6
enot [183]

Answer:

The slope-intercept form equation of the line that passes through (1, 3) and (3, 7) is y = 2x +1.

Step-by-step explanation:

7 0
2 years ago
a plumber charges $45 for the first hour and $30 for each additional hour.how much does he charge if it takes him 4 hours to mak
sveticcg [70]
45+30=75 so 75*4+300 dollars
8 0
3 years ago
If θ=0rad at t=0s, what is the blade's angular position at t=20s
babunello [35]
The attached figure represents the relation between ω (rpm) and t (seconds)
To find the blade's angular position in radians ⇒ ω will be converted from (rpm) to (rad/s)
              ω = 250 (rpm) = 250 * (2π/60) = (25/3)π    rad/s
              ω = 100 (rpm) = 100 * (2π/60) = (10/3)π    rad/s

and from the figure it is clear that the operation is at constant speed but with variable levels
            ⇒   ω = dθ/dt   ⇒   dθ = ω dt

            ∴    θ = ∫₀²⁰  ω dt  
 
while ω is not fixed from (t = 0) to (t =20)
the integral will divided to 3 integrals as follow;
       ω = 0                                          from t = 0  to t = 5
       ω = 250 (rpm) = (25/3)π            from t = 5   to t = 15
       ω = 100 (rpm) = (10/3)π            from t = 15 to t = 20

∴ θ = ∫₀⁵  (0) dt   + ∫₅¹⁵  (25/3)π dt + ∫₁₅²⁰  (10/3)π dt
     
the first integral = 0
the second integral = (25/3)π t = (25/3)π (15-5) = (250/3)π
the third integral = (10/3)π t = (25/3)π (20-15) = (50/3)π

∴ θ = 0 + (250/3)π + (50/3)π = 100 π

while the complete revolution = 2π
so instantaneously at t = 20
∴ θ = 100 π - 50 * 2 π = 0 rad

Which mean:
the blade will be at zero position making no of revolution = (100π)/(2π) = 50
















3 0
3 years ago
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