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viktelen [127]
3 years ago
6

Does anyone know how to find these measures. Pls it’s due in a few hrs

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
3 0
18 is 60+35=95 180-95= 85 so ?=85°
vlabodo [156]3 years ago
3 0

Answer:

17) 120°

18) 85°

Step-by-step explanation:

→ Find the sum of angles in each shape

Quadrilateral = 360°

Triangle = 180°

→ Add the angles together and subtract it from the sum

360 - ( 80 + 80 + 80 ) = 120° for number 17

180 - ( 35 + 60 ) = 85° for number 18

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Drag each relation to the correct location on the table.
asambeis [7]
So what is the question exactly I’m confused on how this is asked
5 0
3 years ago
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How to use scale factor with area of 3600 sq root of 2 and scale factor of 5?​
Tomtit [17]

Answer:

i dont know

Step-by-step explanation:

7 0
3 years ago
what is the perimeter of the triangle. i do not know how to start this problem. any help will be greatly appreciated :))
xz_007 [3.2K]

Given:

Point F,G,H are midpoints of the sides of the triangle CDE.

FG=9,GH=7,CD=24

To find:

The perimeter of the triangle CDE.

Solution:

According to the triangle mid-segment theorem, the length of the mid-segment of a triangle is always half of the base of the triangle.

FG is mid-segment and DE is base. So, by using triangle mid-segment theorem, we get

\dfrac{1}{2}DE=FG

DE=2(FG)

DE=2(9)

DE=18

GH is mid-segment and CE is base. So, by using triangle mid-segment theorem, we get

\dfrac{1}{2}CE=GH

CE=2(GH)

CE=2(7)

CE=14

Now, the perimeter of the triangle CDE is:

Perimeter=CD+DE+CE

Perimeter=24+18+14

Perimeter=56

Therefore, the perimeter of the triangle CDE is 56 units.

7 0
3 years ago
Two streets bounding your triangular lot make an angle of 74∘. The lengths of the two sides of the lot on these streets are 126
ycow [4]

Answer: a) Yes, there is enough fance

b) 58.1° and 47.9°

c) The city will not approve, because 1/3 of the area is just 2220.5ft²

Step-by-step explanation:

a) using law of cosines: x is the side we do not know.

x² = 126² + 110² - 2.126.110.cos74°

x² = 20335.3

x = 142.6 ft

So 150 > 142.6, there is enough fance

b) using law of sine:

sin 74/ 142.6 = sinα/126 = sinβ/110

sin 74/ 142.6 = sinα/126

0.006741 = sinα/126

sinα = 0.849

α = sin⁻¹(0.849)

α = 58.1°

sin 74/ 142.6 = sinβ/110

sin 74/ 142.6 = sinβ/110

0.006741 = sinβ/110

sinβ = 0.741

β = sin⁻¹(0.741)

β = 47.9°

Checking: 74+58.1+47.9 = 180° ok

c) Using Heron A² = p(p-a)(p-b)(p-c)

p = a+b+c/2

p=126+110+142.6/2

p=189.3

A² = 189.3(189.3-126)(189.3-110)(189.3-142.6)

A = 6661.5 ft²

1/3 A = 2220.5

So 2300 >  2220.5. The area you want to build is bigger than the area available.

The city will not approve

7 0
3 years ago
Vertex F of ΔDEF has coordinates (−3, 7). If ΔDEF is reflected over the y-axis, what are the coordinates of vertex Fʹ?
docker41 [41]
The reflection will be on the other side of the y-axis.
Its coordinates will be (3, 7).
5 0
3 years ago
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