3 years ago

Is this right???????

Mathematics

1 answer:

Rina8888 [55]3 years ago

6 0

Answer:

Yes

Step-by-step explanation:

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Expand the following:<br> a) x(x + 2)<br> b) x(2x - 5)<br> c) 2x(3x + 4)<br> d) 6x(x - 2)

TEA [102]

Answer:

solution,

$a. \: x(x + 2) \\ \: \: = x \times x + 2 \times x \\ \: \: = {x}^{2} + 2x$

$b . \: x(2x - 5) \\ \: = x \times 2x - x \times 5 \\ \: \: = 2 {x}^{2} - 5x$

$c. \: 2x(3x + 4) \\ \: = 2x \times 3x + 2x \times 4 \\ \: \: = 6 {x}^{2} + 8x$

$d. \: 6x(x - 2) \\ \: \: = 6x \times x - 6x \times 2 \\ \: \: = 6 {x}^{2} - 12x$

Hope this helps...

Good luck on your assignment..

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3 years ago

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Answer:4

Step-by-step explanation:2x+y+z=2(-2)+3+5=(-4)+3+5=(-1)+5=4

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3 years ago

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In the picture.

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x < 1

Step-by-step explanation:

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