Option B. I am 100% sure that the answer is option B. Hope that helped! :D
If not then I am really sorry!
Answer:
The proportion of children that have an index of at least 110 is 0.0478.
Step-by-step explanation:
The given distribution has a mean of 90 and a standard deviation of 12.
Therefore mean,
= 90 and standard deviation,
= 12.
It is given to find the proportion of children having an index of at least 110.
We can take the variable to be analysed to be x = 110.
Therefore we have to find p(x < 110), which is left tailed.
Using the formula for z which is p( Z <
) we get p(Z <
= 1.67).
So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)
Using the Z - table we can calculate p(Z < 1.67) = 0.9522.
Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478
Therefore the proportion of children that have an index of at least 110 is 0.0478
Point-slope form is y - y1 = m (x + x1)
First you need to find m [slope] by subtract y2 and y1 and divide it by the outcome of x2 - x1
13 - (-9) = 22
-2 - 9 = -11
22/-11 = -2
Plug in the first point (as instructed) into the equation.
y - (-9) = -2 (x - 9)
Simplify the beginning.
y + [9] = [-2] (x + [-9])
(The brackets are the fill in the blanks)
Answer:
46,656
Step-by-step explanation:
6^2x3=
6^6=
6x6x6x6x6x6=
46,656
Hope that helps!
Answer:
4($6.55)/5
Step-by-step explanation:
If five markers cost $6.55
then equate or cross multiply inorder to get the cost of 4 markers.
4($6.55)/5