2(4 - 2r) = -2(r + 5)
First, divide both sides by -2. / Your problem should look like:
Second, regroup your terms. / Your problem should look like:
Third, add 4 to both sides. / Your problem should look like:
Fourth, add r + 5 + 4 to get r + 9. / Your problem should look like:
Fifth, subtract r from both sides. / Your problem should look like:
Sixth, subtract 2r - r to get r. / Your problem should look like:

Answer:
r = 9
The distance between the point (3, 5) and a line with the equation 5x – 3y + 10 = 0 will be 10 / √(34) units.
<h3>What is the distance between a point and a line?</h3>
Let (x₁, y₁) be the point and ax + by + c = 0 be the line.
Then the distance between a point and a line will be

The point (3, 5) and a line with the equation 5x – 3y + 10 = 0.
Then the distance between them will be

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Answer:
c = 5
Step-by-step explanation:
a^2 + b^2 = c^2
3^2 + 4^2 = c^2
9 + 16 = 25
c^2 = 25
sqrt of 25 = 5
c= 5
Answer:
A
Step-by-step explanation: