Answer:
284cm^2
Step-by-step explanation:
first, we split up the shape into seperate sections that we can easily find the areas of.
i will draw vertical lines in the bottom left and right, leaving me with 2 seperate rectangles and 1 irregular pentagon.
we know that these rectangles are 4x8cm, so we do 4 * 8 which gives us 32.
there are 2 of these, so 32 x 2 = 64cm^2.
now, i chose to seperarte the pentagon into a rectangle and a triangle,
and i found the height and width of the rectangle to be (18 - (4+4)) x (8+7), or 10 x 15.
the area of the rectangle is 150cm^2.
now, for the triangle.
the line through the centre of th shape is 22cm long, but we only want the part in the triangle. luckily, there are mesurements that can help us with this.
8 + 7 = 15.
22 - 15 = 7.
now we know that the height of the triangle is 7 cm.
from earlier, we also know the base, which is 10cm.
7 x 10 = 70cm^2.
now we add all these together:
70 + 150 + 64 = 284cm^2
Answer: 1.10
Work: 5 or more raise the next digit, 4 or less keep it
For this case we have:
Let a function of the form 
By definition, to graph 
, where 
, we must move the graph of f (x), h units to the left.
We observe that the red graph has the same form as the black graph, but it is displaced "h" units to the left.
It is observed that 
So, if the black graph is given by, the red graph is given by: 
Answer:
Option A
The red area is the one which solves the system. In fact, we want the area which below both the parabola and the line (since the inequality features a 
sign.
So, the point 
is below the line but above the parabola (blue area), so it is not a solution.
The point 
is above both the line and the parabola (white area), so it is not a solution.
The point 
is below both the line and the parabola (red area), so it is a solution.
So, the point 
is below the parabola but above the line (green area), so it is not a solution.
