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zmey [24]
3 years ago
12

PLEASE help me!!!

Mathematics
1 answer:
densk [106]3 years ago
7 0

Answer:

Step-by-step explanation:

first

3/10 & 7/10

second

5/9 & 4/9

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Which graph shows the solution to the system of linear inequalities? x – 4y < 4 y < x + 1 Image for option 1 Image for opt
slava [35]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

x-4y ----> inequality A

solve for y

-4y

4y>x-4

y> (x/4)-1

The solution of the inequality A is the shaded area above the dashed line

The slope of the dashed line is positive

The y-intercept is the point (0,-1)

The x-intercept is the point (4,0)

y< x+1 ----> inequality B

The solution of the inequality B is the shaded area below the dashed line

The slope of the dashed line is positive

The y-intercept is the point (0,1)

The x-intercept is the point (-1,0)

Using a graphing tool

The solution of the system of inequalities in the attached figure

7 0
3 years ago
MARKING BRANLY You want to plant a flower garden in your yard so that you can make a beautiful bouquet to put on the alter at ch
BabaBlast [244]

Answer:

1. 3 packs of daffodils and 4 packs of tulips

2. then you would have 24 of each

3. $2.29

4. $37.54

5. $34.61

6.$2.93 was saved

7. 3 tulips

8. 12 daffodils

9. 9 tulips

10. 12 daffodils and 15 tulips

theres 2 left. ill let someone else do it

Step-by-step explanation:

3.   4.50*4=18            5.75*3=17.25

18+17.25 -> 35.25*.065=2.29 rounded

4. 35.25+2.29=37.54

5.  35.25-2.75->32.50*.065=2.11       2.11+32.50=34.61

6. 37.54-34.61=2.93

7. 6:8  -> 3:4  ratio -> 3:4

8. 8+4=12

9. 6+3=9

10. 24-12=12           24-9=15

6 0
3 years ago
Read this E[2X^2 â€" Y].
djyliett [7]

Looks like a badly encoded/decoded symbol. It's supposed to be a minus sign, so you're asked to find the expectation of 2<em>X </em>² - <em>Y</em>.

If you don't know how <em>X</em> or <em>Y</em> are distributed, but you know E[<em>X</em> ²] and E[<em>Y</em>], then it's as simple as distributing the expectation over the sum:

E[2<em>X </em>² - <em>Y</em>] = 2 E[<em>X </em>²] - E[<em>Y</em>]

Or, if you're given the expectation and variance of <em>X</em>, you have

Var[<em>X</em>] = E[<em>X</em> ²] - E[<em>X</em>]²

→   E[2<em>X </em>² - <em>Y</em>] = 2 (Var[<em>X</em>] + E[<em>X</em>]²) - E[<em>Y</em>]

Otherwise, you may be given the density function, or joint density, in which case you can determine the expectations by computing an integral or sum.

6 0
3 years ago
Which equation is modeled below?
masha68 [24]

Answer:

your answer is b bud... your welcome....

Step-by-step explanation:

just took the test

5 0
3 years ago
If f(x)=3x^2+2 and g(x)=x^2-9 find (f-g)(x)
miss Akunina [59]

Here given, f(x) = 3x^2+2 and g(x) = x^2-9

we have to find (f-g)(x) which means the subtracting of the functions f(x) and g(x).

(f-g)(x) = f(x) - g(x)

= (3x^2+2) - (x^2-9)

= 3x^2+2 -x^2-(-9)

= 3x^2-x^2+2+9 ( we know that multiplication of negative and negative is positive)

= 2x^2+2+9

=2x^2+11

We have got the required answer here.

(f-g)(x) = 2x^2+11

6 0
3 years ago
Read 2 more answers
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