<h3>Given</h3>
Two positive numbers x and y such that xy = 192
<h3>Find</h3>
The values that minimize x + 3y
<h3>Solution</h3>
y = 192/x . . . . . solve for y
f(x) = x + 3y
f(x) = x + 3(192/x) . . . . . the function we want to minimize
We can find the x that minimizes of f(x) by setting the derivative of f(x) to zero.
... f'(x) = 1 - 576/x² = 0
... 576 = x² . . . . . . . . . . . . multiply by x², add 576
... √576 = x = 24 . . . . . . . take the square root
... y = 192/24 = 8 . . . . . . . find the value of y using the above equation for y
The first number is 24.
The second number is 8.
Answer:
m=2
Step-by-step explanation:
slope is the average rate of change in a specific interval
we can calculate slope in this case with Δy/Δx or (y2-y1)/(x2-x1)
m=(y2-y1)/(x2-x1)
=(-1-7)/(-3-1)
=-8/-4
=2
y - 6 = 4(1 - 4)
y - 6 = 4 - 16
y - 6 = -12
y = -12 + 6
y = -6
This is a horizontal line through the point (0, -6). See below.
