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Tanya [424]
3 years ago
9

Can any one solve this problem ​

Mathematics
1 answer:
ElenaW [278]3 years ago
6 0

Answer:

sorry i can't

please mark me as brainlest

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Give right answers for good review
Rainbow [258]

Answer:

45 im not sure doe

Step-by-step explanation:

6 0
3 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
2 years ago
You get paid $82.50 for working 7 and a half hours why is your rate of pay
Colt1911 [192]
To find the rate of pay, first divide 82.50/7.5 to equal $11/hour.

Your rate of pay is $11 per hour.

Hope this helps!!
6 0
2 years ago
[-1/4/5] × [-7/10+0.95] - [-2/1/4]
const2013 [10]

Answer:

-2.5625

Step-by-step explanation:

<u>1)[-1/4/5] × [-7/10+0.95] - [-2/1/4] turn that into improper fractions</u>

2 1/4=9/4

which is 1 4/5(-7/10+0.95)9/4

<u>2) 1 4/5(-7/10+0.95)= 0.3125</u>

which is 0.3125-9/4

<u>3)Make into decimal form</u>

9/4 equals 2.25

which is 0.3125-2.25

which all equals -2.5625

5 0
3 years ago
Solve For L: A = L ⋅ W ⋅ H<br><br> L=aw/h<br><br> L=wh/a<br><br> L=a/wh<br><br> L=w/ha
bonufazy [111]
Ok so what you're trying to do is get L by itself so to do this you move everything to the other side:
A=L*WH
\frac{A}{WH}=L
So you answer would be: C
8 0
2 years ago
Read 2 more answers
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