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3 years ago

Can any one solve this problem

Mathematics

1 answer:

ElenaW [278]3 years ago

6 0

Answer:

sorry i can't

please mark me as brainlest

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Which of these is equivalent to x + 1 + x + 2 + x + 3 + x + 4?

butalik [34]

Answer:

what are the options?

8 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%7B%20%5Ccos%5E%7B4%7D%5Calpha%7D%20%5C%3A%20%2B%20%20%20%5Csin%5E%7B2%7D%20%5Calpha%20%5C%

timurjin [86]

Answer:

Proved

Step-by-step explanation:

$cos^4\alpha +sin^4\alpha =\frac{1}{4}(3+cos4\alpha )\\\\$

Take the Left Hand Side:

$cos^4\alpha +sin^4\alpha\\\\(cos^2\alpha )^2+(sin^2\alpha )^2\\\\(\frac{1+cos2\alpha }{2})^2+(\frac{1-cos2\alpha }{2})^2 \\\\\frac{1+2cos2\alpha +cos^22\alpha }{4}+\frac{1-2cos2\alpha +cos^22\alpha }{4} \\\\$

$\frac{1+2cos2\alpha +cos^22\alpha +1-2cos2\alpha +cos^22\alpha }{4} \\\\\frac{2+2cos^22\alpha }{4} \\\\\frac{1+cos^22\alpha }{2} \\\\\frac{1}{2}(1+cos^22\alpha )\\\\$

$\frac{1}{2}(1+\frac{1+cos4\alpha }{2})$

$\frac{1}{2}(\frac{2+1+cos4\alpha }{2})\\\\\frac{1}{4}(3+cos4\alpha )\\\\$

Hence Proved!

The following identities were used are attached in an image

3 0

2 years ago

Find the length of the lamppost to the nearest inch.

olganol [36]

Answer:

109 inch

Step-by-step explanation:

we know that

$tan\theta=\frac{Perp}{Base} \\\theta=70\\Base=40 in$

So,

$tan(70)=\frac{Perp}{40} \\\\2.747=\frac{Perp}{40} \\\\2.747\times40=Perp\\\\Perp=109\quad in$

So, length of lamppost is 109 inch

5 0

2 years ago

PLEASE HELP!!! NEED ANSWERS TO THESE QUESTIONS..

yaroslaw [1]

Answer:

12. Option A is correct

13. Option A is correct

14. Option C is correct

15. Option D is correct

16. Option A is correct

Step-by-step explanation:

12) Lowest Common Denominator of

$\frac{p+3}{p^2+7p+10} \,\, and \,\, \frac{p+5}{p^2+5p+6}$

We should find the factors of denominators and then find the LCM of the denominators.Finding LCD is same as finding LCM.

Factors of p^2+7p+10 = p^2 +2p +5p+10 = p(p+2)+5(p+2) = (p+5)(p+2)

Factors of p^2+5p+6 = p^2+2p+3p+6 = p(p+2)+3(p+2) = (p+3) (p+2)

Now, rewriting the above equation with factors and finding the LCM

$\frac{p+3}{(p+5)(p+2)} \,\, and \,\, \frac{p+5}{(p+3)(p+2)}\\$

LCM of (p+5)(p+2) and (p+3)(p+2) = (p+5)(p+3)(p+2)

The LCD is (p+5)(p+3)(p+2).

So, Option A is correct.

13. Divide

$\frac{40x}{64y} \,\,by\,\, \frac{5x}{8y}$

by stands for division. The equation can be written as:

$\frac{40x}{64y}\div\frac{5x}{8y}$

Division sign changed into multiplication, we take reciprocal of second term i.e,

$\frac{40x}{64y}*\frac{8y}{5x}\\\\Solving\\\frac{40x*8y}{64y*5x}\\\\\frac{320xy}{320xy} \\\\1$

So, Option A is correct.

14. Simplify:

$\frac{x+2}{x^2-6x-16} \div \frac{1}{9x} \\$

Factors of x^2-6x-16= x^2 -8x +2x -16 = x(x-8)+2(x-8) = (x-8)(x+2)

Putting factors in the above equation and changing division sign with multiplication we get,

$\frac{x+2}{(x-8)(x+2)} * \frac{9x}{1}\\\frac{9x}{x-8}$

So, Option C is correct.

15. Simplify

$\frac{4}{\frac{1}{4}-\frac{5}{2}}$

Solving denominator,

Taking LCM of 4 and 2 and subtracting we get

$\frac{4}{\frac{1-(5*2)}{4}}\\\frac{4}{\frac{1-10}{4}}\\\frac{4}{\frac{-9}{4}}\\\frac{4*4}{-9}\\\frac{16}{-9} \,\,or\,\,\\\frac{-16}{9}$

Option D is correct.

16. Simplify:

$\frac{7x+42}{x^2+13x+42}$

Making factors of x^2+13x+42= x^2 +6x+7x+42 = x(x+6)+7(x+6) = (x+7)(x+6)

Taking 7 common from numerator and putting factors in denominator we get,

$\frac{7(x+6)}{(x+7)(x+6)}\\\\Cancelling\,\, x+6 \,\, from\,\, numerator \,\, and\,\, \\\\\frac{7}{(x+7)}$

Option A is correct.

8 0

3 years ago

Evaluate 2^3x-1 for x = 1.

inna [77]

Step-by-step explanation:

x=1

=2^3×1-1

=8×1-1

=8-1

8 0

2 years ago

Read 2 more answers

Can any one solve this problem ​

Can any one solve this problem