$(\stackrel{x_1}{6}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{7}-\underset{x_1}{6}}}\implies \cfrac{-1}{1}\implies -1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{-1}(x-\stackrel{x_1}{6}) \\\\\\ y-2=-x+6\implies y=-x+8$

6 0

2 years ago

Write three functions. In the first function, y should vary directly with x. In the second function, y should vary inversely wit

motikmotik

Asked and answered elsewhere.
brainly.com/question/8880788

7 0

3 years ago

Read 2 more answers

The measures of two complementary angles are 12q-9 and 8q+14 . Find the measures of the angles.

Lostsunrise [7]

Answer:

4.25

Step-by-step explanation: 12q - 9 ) + ( 8q + 14 ) = 90

Combine like Terms: 20q + 5 = 90

Subtract 5 from both sides: 20q = 85

Divide both sides by 20: q=4*(1/4)

So your angle is 4(1/4) or 4.25 degrees

8 0

3 years ago

Can any one solve this problem ​

Can any one solve this problem