Answer:
Step-by-step explanation:
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Answer:
0.8333
Step-by-step explanation:
Given :
Mean, X = 100
Lower Specification Limit, LSL = 100 - 10 = 90
Upper Specification Limit, USL = 100 + 10 = 110
Standard Deviation, σ = 4
The process capability index, Cpk;
Cpk = Min[(X - LSL) / 3σ; (USL - X) /3σ]
Cpk = Min[(100 - 90) / 12 ; (110 - 100 ) /12]
Cpk = Min [0.8333 ; 0.8333]
Hence, Cpk = 0.8333
Step-by-step explanation:
Absolute error = 300-286
=14 pounds
Percentage error = 14/286 x 100%
=4.8951
=4.9%
This question is based on the concept of
amount of interest. Therefore, 22,234 would be
the population after 11 years, to the nearest
whole number.
Given:
A town has a population of 13000 and grows at
5% every year.
We need to determined the population after 11
years, to the nearest whole number.
We know that,
Formula =A = P(1+ r)
Where, p be the population. r is the rate and t is
the time.
P= 13000,
r= 5%
†= 11
Now put all these values in formula.
We get,
5
A = 13000(1 +
A
= 13000(1 + 0.05)11
A
= 1300022, 234.41(0.95)
Answer:
k12
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Step-by-step explanation:
