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Dominik [7]
2 years ago
15

A ball is thrown vertically in the air with an initial velocity of 60 feet per second from an initial height of 6 feet. The equa

tion describing the height of the ball at any time is s = -16t^2 +60t+6.
1. how long did it take for the ball to reach its height point?
2. How high did the ball go?
Mathematics
1 answer:
Novosadov [1.4K]2 years ago
8 0

Answer:

  1. 1.875 seconds to reach the maximum height
  2. 62.25 ft

Step-by-step explanation:

The problem can be solved by putting the equation into vertex form.

  s - 6 = -16(t^2 -15/4t)

  s -6 -16(15/8)^2 = -16(t^2 -15/4t +(15/8)^2) . . . . add the square of half the x-coefficient inside parentheses and equivalent amount on the other side of the equation

  s -62.25 = -16(t -15/8)^2 . . . . write as a square, simplify the constant

  s = -16(t -1.875)^2 +62.25 . . . . put in vertex form

The vertex of the downward-opening parabola is at (t, s) = (1.875, 62.25).

1. It took 1.875 seconds for the ball to reach its maximum height.

2. The ball went up to 62.25 feet.

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D.) there is 9a and 6b ,3c and 1 thats four different terms

Step-by-step explanation:

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Step-by-step explanation:

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Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0
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|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

h(x)=\dfrac{1}{3}|x-6|+4

Put the values of x to the equation of the function h(x):

x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6


6 0
2 years ago
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