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3 years ago

PLZ ANSWER QUICK

Mathematics

1 answer:

allochka39001 [22]3 years ago

3 0

Answer: Answer is in the image below.

Step-by-step explanation:

You might be interested in

Which inequality is NOT true when x= -2?

Levart [38]

Answer: D

Step-by-step explanation:

-7 isn't greater than -4

3 0

3 years ago

Find the value of AB. 13 12 A В AB = [?

Sedaia [141]

Answer:

$AB=24$

Step-by-step explanation:

CD is perpendicular to AB

If any radius or diameter is perpendicular to any chord of a circle, then it bisects that chord.

Mean, AB= BE = 12

So, AB = 2(BE)

2(12)= 24

so your answer will be 24

$----------$

hope it helps..

have a great day!!

5 0

3 years ago

If f(x) = _4x _ 1, find f(_2)

tia_tia [17]

The answer is 7

f(x) = -4x - 1
f(-2) = ?

Since f(x) = f(-2), then x = -2. Now just substitute x in the function:
f(-2) = (-4) * (-2) - 1
f(-2) = 8 - 1
f(-2) = 7

8 0

3 years ago

REALLY NEED HELP

artcher [175]

Answer:

Y=-5/3x

Step-by-step explanation:

Use the slope formula and slope-intercept form y=mx+b to find the equation.

3 0

2 years ago

An instructor in a college class recently gave an exam that was worth a total of 100 points. The instructor inadvertently made t

solniwko [45]

Answer:

B) Method 2 will increase the standard deviation of the students' scores.

Step-by-step explanation:

Given that an instructor in a college class recently gave an exam that was worth a total of 100 points.

The average score for his students was 43 and the standard deviation of the scores was 5 points.

And now he is considering two different strategies for rescaling the exam results of which:

Method 1 = Add 17 points to everyone's score.

Method 2 = Multiply everyone's score by 1.7 .

And we have to check what will be the impact of these methods on the standard deviation of the students' scores.

For this let us consider a simple example to understand this:

Firstly, Formula for calculating Standard Deviation = $\sqrt{\frac{\sum (X-Xbar)^{2}}{n-1}}$

Suppose,

X X - Xbar $(X - Xbar)^{2}$

3 3 - 6 = -3 -3 * -3 = 9

5 5 - 6 = -1 -1 * -1 = 1

10 10 - 6 = 4 4 * 4 = 16

Mean of above data, Xbar = $\frac{3+ 5+10}{3}$ = 6

Standard Deviation of data = $\sqrt{\frac{26}{3-1} }$ = 3.6055

Now let us suppose that we multiply each value of above data with 2 so the new data will be:

X X - Xbar $(X - Xbar)^{2}$

3*2 = 6 6 - 12 = -6 -6 * -6 = 36

5*2 = 10 10 - 12 = -2 -2 * -2 = 4

10*2 =20 20 - 12 = 8 8 * 8 = 64

Mean of new data, Xbar = $\frac{6+ 10+20}{3}$ = 12

Standard Deviation of new data = $\sqrt{\frac{104}{3-1} }$ = 7.2111

Hence, we see that when we multiply any value to the data the standard deviation will increase and in other words it will multiplied by that value which value we multiplied with each data value i.e. when we multiply each data value with 2 the standard deviation also get multiplied by as

3.6055 * 2 = 7.2111

Therefore option B is correct that Method 2 will increase the standard deviation of the students' scores.

And on the other hand Similarly by adding any constant to the data the Standard Deviation will remain same. Therefore Method 1 will have no impact on standard deviation of the students' scores.

8 0

3 years ago