is one of the prime factors of the polynomial
<h3>How to factor the expression?</h3>
The question implies that we determine one of the prime factors of the polynomial.
The polynomial is given as:

Expand the polynomial by adding 0's in the form of +a - a

Rearrange the terms

Factorize the expression

Factor out x^6-2x^5+2x^3-3x^2+2x-1

Express x^2 + 2x + 1 as a perfect square

Expand the polynomial by adding 0's in the form of +a - a

Rearrange the terms

Factorize the expression

Factor out x^3-2x^2+x-1

One of the factors of the above polynomial is
.
This is the same as the option (c)
Hence,
is one of the prime factors of the polynomial
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Answer:
x^2 -1
Step-by-step explanation:
-1×x + -1×1 + x×1 + x×x
= x^2 -x +x -1
= x^2 -1

Answer:
5 feet
Step-by-step explanation:
15 divided by 3 equals 5
By the remainder theorem 8x^2 + 4x - 3 when divided by 2x - 1 is
8(1/2)^2 + 4(1/2) - 3 = 2 + 2 - 3 = 1 answer