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gladu [14]
3 years ago
10

What are two integers whose sum is -2 and product is -80?

Mathematics
1 answer:
astra-53 [7]3 years ago
4 0

Answer:

We can write:

x + y = -2

xy = -80

We can rewrite the first equation as x = -y - 2 and then plug that into the second equation to get (-y-2) * y = -80 → -y² - 2y = -80 → y² + 2y - 80 = 0 → (y - 8)(y + 10) = 0 → y = 8, -10. Substituting these values into the first equation we get x = -10, 8 so the answer is (x₁, y₁) = (-10, 8) or (x₂, y₂) = (8, -10).

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Answer:


Step-by-step explanation:

If you treat (x+5) as a single value and (x-2) as the values of x and +2, you can distribute (x+5) to x and +2: ( (x-5)*x + (x-5)*2 ). Then you can treat x-5 as the values of x and -5 and distribute those to the numbers next to them: (×^2 - 5x) + (2x - 10). This results in x^2 -3x - 10.


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Answer:

Step-by-step explanation:

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