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3 years ago

Each polygon is divided into a number of triangles. Find the number of triangles if the number of sides in a polygon is: (a) 6

Mathematics

1 answer:

Serga [27]3 years ago

4 0

Answer:

4 triangles

Step-by-step explanation:

the number of triangles in a polygon is (the number of sides in the polygon - 2)

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Which statement best describes how to determine whether f(x) = 9- 4x4 is an odd function?

vitfil [10]

Answer:

Option C.

Step-by-step explanation:

Note: In the given function the power of x should be 2 instead of 4, otherwise all options are incorrect.

Consider the given function is

$f(x)=9-4x^2$

If $f(-x)=f(x)$ , then $f(x)$ is an even function.

If $f(-x)=-f(x)$ , then $f(x)$ is an odd function.

Now, substitute x=-x in the given function.

$f(-x)=9-4(-x)^2$

$f(-x)=9-4(x)^2$

$f(-x)=f(x)$

So, the given function not an odd function. It means it is an even function.

To check whether the given function is odd, we have to determine whether $9-4(-x)^2$ is equivalent to $-(9-4(x)^2)$ .

Therefore, the correct option is C.

6 0

3 years ago

Help me? idk the answer :P

Alexus [3.1K]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\
\left( 2^8\cdot 3^{-5}\cdot 6^0 \right)^{-2}\left( \cfrac{3^{-2}}{2^3} \right)^4\cdot 2^{28}\impliedby \textit{let's do the first group}
\\\\
-------------------------------\\\\
$

$\bf \left( 2^8\cdot \cfrac{1}{3^5}\cdot 1 \right)^{-2}\implies \left( \cfrac{2^8}{3^5} \right)^{-2}\implies \left( \cfrac{3^5}{2^8} \right)^{2}\implies \cfrac{3^{2\cdot 5}}{2^{2\cdot 8}}\implies \boxed{\cfrac{3^{10}}{2^{16}}}\\\\
-------------------------------\\\\
\textit{now the second group}\qquad \left( \cfrac{3^{-2}}{2^3} \right)^4\implies \left( \cfrac{\frac{1}{3^2}}{2^3} \right)^4\implies \left( \cfrac{1}{2^3\cdot 3^2} \right)^4$

$\bf \cfrac{1^4}{2^{4\cdot 3}\cdot 3^{4\cdot 2}}\implies \boxed{\cfrac{1}{2^{12}\cdot 3^8}}\\\\
-------------------------------\\\\
\textit{so we end up with\qquad }\cfrac{3^{10}}{2^{16}}\cdot \cfrac{1}{2^{12}\cdot 3^8}\cdot 2^{28}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{16}\cdot 2^{12}\cdot 3^8}
\\\\\\
\cfrac{3^{10}\cdot 2^{28}}{2^{16+12}\cdot 3^8}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{28}\cdot 3^8}\implies 3^{10}\cdot 2^{28}\cdot 2^{-28}\cdot 3^{-8}$

$\bf 3^{10-8}\cdot 2^{28-28}\implies 3^2\cdot 1\implies 3^2\implies 9$

7 0

2 years ago

Please I needa answer !!

Alecsey [184]

Answer:

the answer is B and C

Step-by-step explanation:

7 0

3 years ago

Determine if triangle DEF with coordinates D (3, 2), E (4, 6), and F (7, 3) is an equilateral triangle. Use evidence to support

Anna [14]

Use the formula d=sqrt[(x₂-x₁)^2+(y₂-y₁)^2] to find distance between 2 points.
DE = √17
EF = √18
FD = √17
See the attachment for the complete workout.
Since,All the sides are not same to make an equilateral triangle.
So its not an equilateral triangle

6 0

3 years ago

Jumping makes a frog so tired, each successive jump is 2/3 the distance of the previous hump. If a frog jumps 24 cm on its first

kodGreya [7K]

7 cm, after 4 jumps the frog 7.111... cm.

5 0

3 years ago