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nignag [31]
3 years ago
9

In the triangle above, the cosine of a is 0.8.What is sine of b?

Mathematics
1 answer:
Natalka [10]3 years ago
5 0

Answer:

sin b = 0.8

Step-by-step explanation:

Since a and b are complementary angles , then

sin b = cos a = 0.8

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Parallelogram square rectangle
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12-(-4)(-3), evaluate please
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Answer:

0

Step-by-step explanation:

12-(-4)(-3)

-3 x -4 = 12

12 - 12= 0

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An angle bisector has been created. Solve for x.
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3 years ago
Complete the table of values fory=2x^2+x
Semmy [17]

Complete question:

y = 2x² + 2x - 3

x = -2 -1 0 1 2

Answer:

<u>Complete table of values</u>

x:   -2        -1         0          1          2

y:    1          -3       -3          1         9

Step-by-step explanation:

Given;

y = 2x² + 2x - 3

To complete the table of values of the equation above, we substitute the value of x into the given equation and solve for y.

when, x = -2

y = 2(-2)² + 2(-2) - 3

y = 8 - 4 - 3

y = 1

when x = -1

y = 2(-1)² + 2(-1) - 3

y = 2 - 2 - 3

y = -3

when x = 0

y = 2(0)² + 2(0) - 3

y = 0 - 0 - 3

y = -3

when x = 1

y = 2(1)² + 2(1) - 3

y = 2 + 2 - 3

y = 1

when x = 2

y = 2(2)² + 2(2) - 3

y = 8 + 4 - 3

y = 9

<u>Complete table</u>

x:   -2        -1         0          1          2

y:    1          -3       -3          1         9

7 0
3 years ago
Which equation could be used to calculate the sum of the geometric series? One-third + two-ninths + StartFraction 4 Over 27 EndF
kondaur [170]

Answer:

S 5 = StartFraction one-third (1 minus (two-thirds) Superscript 5 Baseline) Over (1 minus two-thirds) EndFraction

Step-by-step explanation:

Given the geometric series:

1/3+2/9+4/27+8/81+16/243

First we must know that the series is a finite series with just 5terms.

Before we can know the formula to calculate sum of the first five terms of the series, we must determine its common ratio (r) first.

r = (2/9)÷1/3 = 4/27÷2/9= 8/81÷4/27

r = 2/9 × 3/1

r = 2/3

Similarly;

r = 4/27×9/2

r = 2/3

Since all values of r is the as them the common ratio is 2/3.

If r< 1 in geometric series, then the formula for finding its sum is applicable

Sn = a(1-rⁿ)/1-r

a is the first term = 1/3

r is the common ratio = 2/3

n is the number of terms = 5

Substituting the values in the formula we have:

S5 = 1/3{1-(2/3)^5}/1-2/3

This gives the requires equation

S 5 = StartFraction one-third (1 minus (two-thirds) Superscript 5 Baseline) Over (1 minus two-thirds) EndFraction

4 0
3 years ago
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