In the triangle above, the cosine of a is 0.8.What is sine of b?
1 answer:
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Answer:
The second one; x²+7x+12
Step-by-step explanation:
So, since the beginning lengths of the square is x and x, the area of the square is x².
But then, you add 3 to one length, so that side is now (x+3), and then you add 4 to the width, so that is now (x+4).
Finally, you would multiply them together to get the equation you would use to find the new area.
For this, you would cross-multiply everything together; the x in the length by the x in the width, the x in the length by the 4 in the width, the 3 in the length by the x in the width, and then the 3 in the length by the 4 in the width. Now, all you have to do is add all of these together to get your answer.
Here's the work:
Solving of the system equation: 2x-y=-13 ⇒(1) and y=x+9 ⇒(2)
by substituting from (2) at (1)
2x-(x+9)=-13
2x-x-9=-13
x=-4 ⇒ substituting at (2) ∴ y = -4+9 = 5
<span>The point that represents the solution to the system = (-4,5)
========================================================
</span>
solving of the system equation: 3x+2y=10 ⇒(1) and 6x-y=10 ⇒(2)
by multiplying equation (2) ⇒ 12x-2y=20 ⇒(3)
adding (1) and (3)
15 x = 30 ⇒ x=2
from equation (2) 6x-y =10 ⇒⇒⇒ y = 6x-10 =12-10=2
<span>The point that represents the solution to the system = (2,2)
=======================================================
</span>
<span>solving of the system equation: 4x-3y=5 ⇒(1) and 3x+2y=-9 ⇒(2)
solve for x, y
we find x=-1 and y=-3
</span>
<span>The point that represents the solution to the system = (-1,-3)
</span>=======================================================
solving of the system equation: x+y=7 ⇒(1) and x-y=-1 ⇒(2)
adding (1) and (2)
2x=6 ⇒⇒⇒ x = 3
substitute at (1)
y =7-x=7-3=4
<span>The point that represents the solution to the system = (3,4)
=======================================================
</span>solving of the system equation: y=3x-7 ⇒(1) and y=2x-5 ⇒(2)
equating (1) and (2)
solve for x and y
we find x=2 ⇒⇒⇒ y = -1
<span>The point that represents the solution to the system = (2,-1)
=======================================================
</span>
The system equation : y = 6 and x =-5
<span>The point that represents the solution to the system = (-5,6)
=======================================================
The attached figure represent a conclusion for the answer
</span>
by substituting from (2) at (1)
2x-(x+9)=-13
2x-x-9=-13
x=-4 ⇒ substituting at (2) ∴ y = -4+9 = 5
<span>The point that represents the solution to the system = (-4,5)
========================================================
</span>
solving of the system equation: 3x+2y=10 ⇒(1) and 6x-y=10 ⇒(2)
by multiplying equation (2) ⇒ 12x-2y=20 ⇒(3)
adding (1) and (3)
15 x = 30 ⇒ x=2
from equation (2) 6x-y =10 ⇒⇒⇒ y = 6x-10 =12-10=2
<span>The point that represents the solution to the system = (2,2)
=======================================================
</span>
<span>solving of the system equation: 4x-3y=5 ⇒(1) and 3x+2y=-9 ⇒(2)
solve for x, y
we find x=-1 and y=-3
</span>
<span>The point that represents the solution to the system = (-1,-3)
</span>=======================================================
solving of the system equation: x+y=7 ⇒(1) and x-y=-1 ⇒(2)
adding (1) and (2)
2x=6 ⇒⇒⇒ x = 3
substitute at (1)
y =7-x=7-3=4
<span>The point that represents the solution to the system = (3,4)
=======================================================
</span>solving of the system equation: y=3x-7 ⇒(1) and y=2x-5 ⇒(2)
equating (1) and (2)
solve for x and y
we find x=2 ⇒⇒⇒ y = -1
<span>The point that represents the solution to the system = (2,-1)
=======================================================
</span>
The system equation : y = 6 and x =-5
<span>The point that represents the solution to the system = (-5,6)
=======================================================
The attached figure represent a conclusion for the answer
</span>