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2 years ago

5/3 to the power of 3

1 answer:

6 0

So it looks like this: (5/3)^3. It is easier to distribute the third power to both values: (5^3)/(3^3). 5 to the third power is 125 and 3 to the third power is 27. Final answer is 125/27.

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I need help please and thank you

ozzi

Answer:

-2480

Step-by-step explanation:

31 * -80 =-2480

Not sure how to explain this more, but I hope this helps!

3 0

3 years ago

Read 2 more answers

Need help......................

Lera25 [3.4K]

I don’t really know it sry

5 0

2 years ago

A taxi driver had 27 fares to and from the airport last Monday. The price for a ride to the airport is $14, and the price for a

OLga [1]

Answer:

(15, 12)

Step-by-step explanation:

Let's generate two systems of equations that fit this scenario.

Number of trips to the airport = x

Number of trips from the airport = y

Total number of trips to and from the airport = 27

Thus:

$x + y = 27$ => equation 1.

Total price for trips to the Airport = 14*x = 14x

Total price of trips from the airport = 7*y = 7y

Total collected for the day = $294

Thus:

$14x + 7y = 294$ => equation 2.

Multiply equation 1 by 7, and multiply equation 2 by 1 to make both equations equivalent.

7 × $x + y = 27$

1 × $14x + 7y = 294$

Thus:

$7x + 7y = 189$ => equation 3

$14x + 7y = 294$ => equation 4

Subtract equation 4 from equation 3

-7x = -105

Divide both sides by -7

x = 15

Substitute x = 15 in equation 1

$x + y = 27$

$15 + y = 27$

Subtract both sides by 15

$y = 27 - 15$

$y = 12$

The ordered pair would be (15, 12)

7 0

2 years ago

A study of 25 graduates of 4-year public colleges revealed the mean amount owed by a student in student loans was $55,051. The s

Harman [31]

Answer:

Step 1

The data represent amount.

A 90% confidence interval for the population mean is,

First, compute t-critical value then find confidence interval.

The t critical value for the 90% confidence interval is,

The sample size is small and two-tailed test. Look in the column headed and the row headed in the t distribution table by using degree of freedom is,

The t critical value for the 90% confidence interval is 1.711.

A 90% confidence interval for the population mean is .

Step 2

It is reasonable to conclude that mean of the population is actually $55000 due to a 90% confidence intrerval for population mean is between $52461.23 and $57640.77 does include $55000.

The data represent amount.

A 90% confidence interval for the population mean is,

First, compute t-critical value then find confidence interval.

The t critical value for the 90% confidence interval is,

The sample size is small and two-tailed test. Look in the column headed and the row headed in the t distribution table by using degree of freedom is,

The t critical value for the 90% confidence interval is 1.711.

A 90% confidence interval for the population mean is .

It is reasonable to conclude that mean of the population is actually $55000 due to a 90% confidence intrerval for population mean is between $52461.23 and $57640.77 does include $55000.

5 0

2 years ago

Molly has $60 in a savings account that earns 5% simple interest annually. How much interest will she earn in 6 months?

mrs_skeptik [129]

Answer:

The interest is $1.5 and the amount is $61.5.

Step-by-step explanation:

3 0

2 years ago