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3 years ago

Which binomial is a factor of 9x^2+24xy+16y^2

Mathematics

2 answers:

gregori [183]3 years ago

7 0

Answer: (3x + 4y)(3x + 4y)

Step-by-step explanation: So you are supposed to "unfoil". So you would find two numbers multiplied together to make 9x^2 which would be 3x. Then you would find two numbers that can be multiplied together to get 16y^2 which would be 4y. To check your work, you do 3x times 3x. Then 4y times 4y. Then 4y times 3x plus 3x times 4y. You get 9x^2 + 24xy plus 16y^2.

Cloud [144]3 years ago

7 0

3x+4y for people who are using apx

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maria [59]

Answer:

14/33

Step-by-step explanation:

The total amount of beads is 8+4 = 12. 8 of these are black beads, so that is what we want, so 8/12 or 2/3. For the second one, one black bead is already taken so 8-1 = 7 are left and for the total 12 - 1 = 11 are left, so 7/11. Multiply this by 2/3 and we get 14/33.

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3 years ago

Evaluate 13-0.75w+8x when W=12and x =1/2.

My name is Ann [436]

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3 years ago

Change 2x-y=-4 into slope-intercept form with steps

Art [367]

Answer:

Y=2x+4

Step-by-step explanation:

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3 years ago

The faces on a number cube are labled 1,2,2,3,4, and 5the number cube is rolled 114 times how many times would you expect the nu

Mrac [35]

Given:

The faces on a number cube are labeled 1,2,2,3,4, and 5.

The number cube is rolled 114 times.

To find:

How many times would you expect the number 2 to appear?

Solution:

We have,

Total outcomes = 1,2,2,3,4, and 5.

Number of total outcomes = 6

Favorable outcomes = 2 and 2

Number of favorable outcomes = 2

The probability of getting 2 is:

$P(2)=\dfrac{\text{Number of favorable outcomes}}{\text{Number of total outcomes}}$

$P(2)=\dfrac{2}{6}$

$P(2)=\dfrac{1}{3}$

Now, the expected number of times when 2 to appear is:

$E(x)=114\times P(2)$

$E(x)=114\times \dfrac{1}{3}$

$E(x)=38$

Therefore, the expected number of times is 38.

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3 years ago

A stone is thrown vertically upward from a platform that is 20 feet height at a rate of 160 ft/sec. Use the quadratic function h

Nutka1998 [239]

Check the picture below.

$\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-16}x^2\stackrel{\stackrel{b}{\downarrow }}{+160}x\stackrel{\stackrel{c}{\downarrow }}{+20} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)$

$\left(-\cfrac{ 160}{2(-16)}~~~~ ,~~~~ 20-\cfrac{ (160)^2}{4(-16)}\right) \implies \left( - \cfrac{ 160 }{ -32 }~~,~~20 - \cfrac{ 25600 }{ -64 } \right) \\\\\\ \left( 5 ~~~~ ,~~~~ 20 +400 \right)\implies (\stackrel{seconds}{5}~~,~~\stackrel{feet}{420})$

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1 year ago