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zavuch27 [327]
3 years ago
10

A basketball player has a 25% accuracy rate at making three-point shots. Mark thought it was reasonable that each attempt was in

dependent and the probability stayed at 25% for this player. P (X equals k )equals (1 minus p )to the power of k minus 1 end exponent p Using the geometric distribution formula, what is the probability that the basketball player makes his first three-point shot on the third attempt
Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0
6 is the best answer y’all
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Please help, and stop sending me links
otez555 [7]

Answer:

I need this answer as well

Step-by-step explanation:

4 0
3 years ago
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30 ft
Alex

Answer:

32 ft

Step-by-step explanation:

find the area of the large rectangle:

30 x 16 = 480

find the area of the small rectangle:

10 x 8 = 80

subract the small rectangle from the big rectangle to get the area of the shaded region:

480 - 80 = 400

now plug this area and the height into the equation for triangle area:

A = bh/2

400 = b(25)/2 multiply both sides by 2

2(400) = 2(25b/2)

800 = 25b divide both sides by 25

800/25 = 25b/25

32 = b

6 0
3 years ago
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In a 45-45-90 triangle, what is the length of the hypotenuse when the length of one of the legs is 8 in.?
aliya0001 [1]
The answer is A
the legs are x and the hypotenuse is x√2.
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6 0
4 years ago
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Part of a university's professor's job is to publish his or her research. This task often entails reading a variety of journal a
goblinko [34]

Answer:

(18.1042, 35.2292) is a 90% confidence interval for the mean number of journal articles read monthly by professors.

Step-by-step explanation:

We have a small sample of size n = 12, \bar{x} =  26.6667 and s = 16.5163. A pivotal quantity for this case is given by T = \frac{\bar{X}-\mu}{S/\sqrt{n}} which has a t distribution with n-1 degrees of freedom if we suppose that we take the sample from the normal population. The confidence interval is given by \bar{x}\pm t_{\alpha/2}(\frac{s}{\sqrt{n}}) where t_{\alpha/2} is the \alpha/2th quantile of the t distribution with n - 1 = 12 - 1 = 11 degrees of freedom. As we want the 90% confidence interval, we have that \alpha = 0.1 and the confidence interval is 26.6667\pm t_{0.05}(\frac{16.5163}{\sqrt{12}}) where t_{0.05} is the 5th quantile of the t distribution with 11 df, i.e., t_{0.05} = -1.7959. Then, we have 26.6667\pm (-1.7959)(\frac{16.5163}{\sqrt{12}}) and the 90% confidence interval is given by (18.1042, 35.2292).

6 0
3 years ago
Which linear regression equation best fits the given points? (0,8), (1,6), (1,7), (2,4), (2,5), (4,1), (5,1), (6,0)
irina1246 [14]
C. is the answer thank you
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3 years ago
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