We have to calculate the area of the polygon. This polygon is made of a parallelogram and the right triangle. The area of the triangle: A 1 = a * b / 2 = 8 * 17 / 2 = 136 / 2 = 68 cm^2. The area of a parallelogram : A 2 = a * h = 17 * 6 = 102 cm^2. Finally: A ( polygon ) = A 1 + A 2 = 68 + 102 = 170. Answer: B. 170 cm^2.<span> </span>
The length of PQ is 19.66 units
Step-by-step explanation:
The given is:
1. PK = KQ = 12
2. m∠P = 35º
We need to find the length pf PQ
∵ PK = KQ
∴ m∠P = m∠Q
∵ m∠P = 35°
∴ m∠Q = 35°
The sum of measures of the angles of a triangle is 180°
∴ m∠P + m∠Q + m∠K = 180°
∴ 35 + 35 + m∠K = 180
∴ 70 + m∠K = 180
- Subtract 70 from both sides
∴ m∠K = 110°
Let us use cosine rule to find the length of PQ
∵ PQ =
∵ PK = 12 , KQ = 12 , m∠K = 110°
- Substitute these values in the rule
∴ PQ =
∴ PQ = 19.66
The length of PQ is 19.66 units
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You can learn more about triangle in brainly.com/question/12985572
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It has 42 vertices, my friend.<span />
Step-by-step explanation:
(2ab-7a-4) - (7ab-4)
= 2ab - 7a - 4 - 7ab +4
(-) × (-) = (+)
(-) × (-) = (+)-(-4)= +4
then 4 will be cancelled
= 2ab - 7ab - 7a
= -5ab -7a
Answer:
1
Step-by-step explanation:
Simply plug in 0 for x:
g(0) = 5x + 1
g(0) = 5(0) + 1
g(0) = 1