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3 years ago

Please help 4 questions for 10 points!!!

Mathematics

2 answers:

exis [7]3 years ago

8 0

Answer:

Step-by-step explanation:

1)4(20+3)

2)4(20+22)

3)6.40+6.5

4)12(2+7)

galben [10]3 years ago

8 0

I agree with the person above

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Steve had 48 chocolates but decided to give 8 chocolates to each of his coworkers,

Lunna [17]

Answer:

48 - 8c

Step-by-step explanation:

let c be the number of coworkers

48 - 8c would be the expression because it starts with 48 and for every coworker 8 is subtracted.

5 0

3 years ago

Read 2 more answers

During a tunnel construction project, engineers used explosives to excavate partway into a mountain. Because of time constraints

AnnyKZ [126]

The given data can be tabulated as:

number of days,x length of tunnel (ft), y

0 225

5 350

20 725

30 975

55 1,600

To check if the growth is linear, the slope at points (0, 225) and (5, 350), and (0, 225) and (20, 725) should be equal. The formula for slope is:

m = (y2 – y1) / (x2 – x1)

Finding for slope (0, 225) and (5, 350):

m = (350 – 225) / (5 – 0) = 25

Finding for slope (0, 225) and (20, 725):

m = (725 – 225) / (20 – 0) = 25

Therefore the equation is linear in the form of:

y = mx + b

where b is the value of y at x = 0, so b = 225

The complete equation is:

y = 25x + 225

At x = 86 days

y = 25(86) + 225

y = 2,375 ft

Therefore the length of the completed tunnel is 2,375 feet.

5 0

3 years ago

In the country of United States of Heightlandia, the height measurements of ten-year-old children are approximately normally dis

aliya0001 [1]

(A)

P(X < 61.25) = P((X - 55.4)/4.1 < (61.25 - 55.4)/4.1)

… ≈ P(Z ≤ 0.1427)

… ≈ 0.5567

(B)

P(X > 46.5) = P((X - 55.4)/4.1 > (46.5 - 55.4)/4.1)

… ≈ P(Z > -2.1707)

… ≈ 1 - P(Z ≤ -2.1707)

… ≈ 0.9850

5 0

3 years ago

YALL PLSSSSSSSS HELP IM SHAKING I NEED HELP PLSS

Vilka [71]

Answer:

someone is adding dont worrie

Step-by-step explanation:

8 0

2 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago