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QveST [7]
3 years ago
8

Can someone help me find the standard deviation of this data set plssss

Mathematics
2 answers:
Svetllana [295]3 years ago
7 0

since it was too long, I just made this python code in order to solve for it:

from math import *

data = [35, 27, 24, 42, 25, 31, 41, 34, 32, 46, 29, 44, 29, 35, 39, 27, 41, 63, 52, 31, 38, 46, 39, 27, 58, 32, 33, 47, 36, 28, 65, 53, 40, 32, 39, 44, 48, 59, 46, 62, 22, 39, 35, 29, 36, 66, 33, 45, 50, 62, 27, 27, 41, 33, 54, 44, 26, 31, 45, 33, 42, 63, 51, 70, 42, 53, 38, 28, 35, 49, 47, 54, 44, 40, 39, 62, 30, 35, 38, 26, 34, 61, 19, 30, 34, 26, 41, 35, 26, 54, 28, 32, 50, 27, 31, 35, 38, 26, 47, 30, 28, 62, 57, 56, 30, 32, 31, 36, 32, 42, 33, 51, 35, 30, 28, 20, 23, 27, 33, 36, 35, 42, 43, 28, 36, 44, 58, 41, 36, 37, 49, 34, 23, 39, 34, 37, 62, 23, 28, 26, 29, 30, 37, 46, 43, 56, 53, 31, 36, 44, 39, 51, 21, 51, 34, 30, 25, 31, 38, 52, 49, 43, 50, 31, 36, 32, 28, 44, 61, 57, 24, 63, 28, 31, 32, 26, 28]

def stand_dev(list_n):

x = 0

sum_num = 0

for x in list_n:

sum_num += list_n[x]

sum_of_n = sum_num

mean = float(sum_of_n / len(list_n))

float(mean)

i = 0

e = 0.0

for i in list_n:

subtract_then_square = (list_n[i] - mean)**2

e += subtract_then_square

result1 = e

new_mean = result1 / len(list_n)

final_result = float(sqrt(new_mean))

return final_result

print(stand_dev(data))

basically, the first chunk of the code calculated the mean of the data. The second chunk would take all of the values from the data, subtract it from the mean, and then square it. I then took the sum of all the new values and average it to get the new mean, then square rooted the new mean to get the answer.

it should be ~= 11.713, but you can always check it by searching up a python compiler online and then insert in the data.

Liula [17]3 years ago
4 0

Answer:

I used MS excel and got the attached results.

Note the data is sorted and the data size is 177.

The answer I got is 11.31045226

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