Just divide 78 with 11, 7.090909090909091.
The value of z is 13,184 because you first multiply 37 times 40 and you get 1,480 , so then you subtract the area which is 14,664 minus 1,480 and the answer you get is z
3) x² - 121 = 0
x² = 121
x' = +√121
x' = 11
_______________
x'' = - √121
x'' = -11
Solution ⇒ S{-11 ; 11 } or (x-11)(x+11)
4) 4x² + 144 = 0
4x² = -144
x² = -144 / 4
x² = -36
x = √-36
No solution ⇒ S = ∅
5) z²+10z+21 = 0
Δ = 10² - 4(1)(21)
Δ = 100 - 84
Δ = 16
x' = (-10+4) / 2 = -6/2 = -3
x'' = (-10-4) / 2 = -14/2 = -7
Solution ⇒ S{ -7 ; -3} or (x+3)(x+7)
Answer: B
Step-by-step explanation:
Answer:
pretty sure its d
Step-by-step explanation:
the quadrant one function has asymptotes at y=0 and x=0 so x and y have to stay positive
the quadrant three function has asymptotes at y=0 and x=0 so x and y have to stay negative
