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kherson [118]
3 years ago
14

How do you graph a solution set of an inequality that only has whole numbers

Mathematics
1 answer:
fomenos3 years ago
5 0

Answer:

Step-by-step explanation:

A solution set is the set of values which satisfy a given inequality. It means, each and every value in the solution set will satisfy the inequality and no other value will satisfy the inequality.

Example:

Solve 2x + 3 ≤ 7, where x is a natural number.

Solution:

2x + 3 ≤ 7

Subtracting 3 from both the sides,

2x ≤ 4

Dividing both sides by 2,

x ≤ 2

Since  x is a natural number,

Solution set = {1,2}.

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A sociologist recently conducted a survey of senior citizens who have net worths too high to qualify for Medicaid but have no pr
hjlf

Answer:

a) s= 9.74

D. 9.74

b) Median= 74

B. 74

Step-by-step explanation:

Part a

We have the following dataset given:

69 74 75 62 70 93 64 69 61 88 67 77 87 90 66 91 77 63 82 82 71 74 76 65 83

We can begin calculating the sample mean with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X = 75.04

Now we can calculate the sample deviation with the following formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i-\bar X)^2}{n-1}}

And after replace we got:

s= 9.74

Part b

For this case we need to sort the value on increasing way:

[1] 61 62 63 64 65 66 67 69 69 70 71 74 74 75 76 77 77 82 82 83 87 88 90 91 93

And the median would be the value in the position 13 and we got:

Median= 74

6 0
3 years ago
True or false.
krek1111 [17]

Answer:

True

Step-by-step explanation:

hope this helps you

7 0
2 years ago
(60 POINTS) PLEASE HELP ME!!!
Elan Coil [88]

Answer:

the second option

Step-by-step explanation:

The second option because there is no pattern.

8 0
3 years ago
Read 2 more answers
Previously, an organization reported that teenagers spent 24.5 hours per week, on average, on the phone. The organization thinks
Lena [83]

Answer:

We need to develop a one-tail t-student test ( test to the right )

We reject H₀  we find evidence that student spent more than 24,5 hours on the phone

Step-by-step explanation:

Sample size  n = 15     n < 30

And we were asked if the mean is higher than, therefore is a one-tail t-student test ( test to the right )

Population mean   μ₀  = 24,5

Sample mean   μ  =  25,7

Sample standard deviation s = 2

Hypothesis Test:

Null Hypothesis      H₀                             μ  =  μ₀

Alternative Hypothesis     Hₐ                  μ  >  μ₀

t (c) =  ?

We will define CI = 95 %  then   α = 5 %   α = 0,05    α/2 =  0,025

n = 15     then degree of freedom    df = 14

From t-student table  we get:  t(c) = 2,1448

And  t(s)

t(s) = ( μ  -  μ₀  ) / s/√n

t(s) = (25,7 - 24,5) /2/√15

t(s) = 2,3237

Now we compare   t(c)   and  t(s)

t(c)  =  2,1448         t(s)  = 2,3237

t(s) > t(c)

Then we are in the rejection region we reject H₀   we have evidence at 95% of CI that students spend more than 24,5 hours per week on the phone

8 0
3 years ago
What of these numbers is a prime number 1,11,21,51
Zepler [3.9K]
11. It is not the multiple of any numbers smaller than it
7 0
3 years ago
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