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3 years ago

How do you graph a solution set of an inequality that only has whole numbers

Mathematics

1 answer:

fomenos3 years ago

5 0

Answer:

Step-by-step explanation:

A solution set is the set of values which satisfy a given inequality. It means, each and every value in the solution set will satisfy the inequality and no other value will satisfy the inequality.

Example:

Solve 2x + 3 ≤ 7, where x is a natural number.

Solution:

2x + 3 ≤ 7

Subtracting 3 from both the sides,

2x ≤ 4

Dividing both sides by 2,

x ≤ 2

Since x is a natural number,

Solution set = {1,2}.

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A sociologist recently conducted a survey of senior citizens who have net worths too high to qualify for Medicaid but have no pr

hjlf

Answer:

a) $s= 9.74$

D. 9.74

b) $Median= 74$

B. 74

Step-by-step explanation:

Part a

We have the following dataset given:

69 74 75 62 70 93 64 69 61 88 67 77 87 90 66 91 77 63 82 82 71 74 76 65 83

We can begin calculating the sample mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And replacing we got:

$\bar X = 75.04$

Now we can calculate the sample deviation with the following formula:

$s =\sqrt{\frac{\sum_{i=1}^n (X_i-\bar X)^2}{n-1}}$

And after replace we got:

$s= 9.74$

Part b

For this case we need to sort the value on increasing way:

[1] 61 62 63 64 65 66 67 69 69 70 71 74 74 75 76 77 77 82 82 83 87 88 90 91 93

And the median would be the value in the position 13 and we got:

$Median= 74$

6 0

3 years ago

True or false.

krek1111 [17]

Answer:

True

Step-by-step explanation:

hope this helps you

7 0

2 years ago

(60 POINTS) PLEASE HELP ME!!!

Elan Coil [88]

Answer:

the second option

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

Previously, an organization reported that teenagers spent 24.5 hours per week, on average, on the phone. The organization thinks

Lena [83]

Answer:

We need to develop a one-tail t-student test ( test to the right )

We reject H₀ we find evidence that student spent more than 24,5 hours on the phone

Step-by-step explanation:

Sample size n = 15 n < 30

And we were asked if the mean is higher than, therefore is a one-tail t-student test ( test to the right )

Population mean μ₀ = 24,5

Sample mean μ = 25,7

Sample standard deviation s = 2

Hypothesis Test:

Null Hypothesis H₀ μ = μ₀

Alternative Hypothesis Hₐ μ > μ₀

t (c) = ?

We will define CI = 95 % then α = 5 % α = 0,05 α/2 = 0,025

n = 15 then degree of freedom df = 14

From t-student table we get: t(c) = 2,1448

And t(s)

t(s) = ( μ - μ₀ ) / s/√n

t(s) = (25,7 - 24,5) /2/√15

t(s) = 2,3237

Now we compare t(c) and t(s)

t(c) = 2,1448 t(s) = 2,3237

t(s) > t(c)

Then we are in the rejection region we reject H₀ we have evidence at 95% of CI that students spend more than 24,5 hours per week on the phone

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3 years ago

What of these numbers is a prime number 1,11,21,51

Zepler [3.9K]

11. It is not the multiple of any numbers smaller than it

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